Php 将一个方法放在另一个方法的参数中?

Php 将一个方法放在另一个方法的参数中?,php,Php,我有以下两行: pll__("No Coments"); ?> <?php comments_number('No Comments','1 Comment','% Comments'); ?> pll_uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 我想将第二个方法的'No Comments'、'1 Comment'、'%Comments'部分替换为pll\uuuunts(“No Coment

我有以下两行:

pll__("No Coments"); ?>

<?php comments_number('No Comments','1 Comment','% Comments'); ?>
pll_uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
我想将第二个方法的
'No Comments'、'1 Comment'、'%Comments'
部分替换为
pll\uuuunts(“No Coments”)、pll\uunts(“1 Coments”)
,等等

我不确定正确的方法是什么,特别是最后一部分(
'%Comments'
)。

确定您可以这样做:

comments_number(pll__('No Comments'), pll__('1 Comment'), pll__('% Comments'));

什么代表pll功能?这是干什么的?@Matei Mihai这就像是
\uuuuuu()