Php 将一个方法放在另一个方法的参数中?
我有以下两行:Php 将一个方法放在另一个方法的参数中?,php,Php,我有以下两行: pll__("No Coments"); ?> <?php comments_number('No Comments','1 Comment','% Comments'); ?> pll_uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu 我想将第二个方法的'No Comments'、'1 Comment'、'%Comments'部分替换为pll\uuuunts(“No Coment
pll__("No Coments"); ?>
<?php comments_number('No Comments','1 Comment','% Comments'); ?>
pll_uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
我想将第二个方法的'No Comments'、'1 Comment'、'%Comments'
部分替换为pll\uuuunts(“No Coments”)、pll\uunts(“1 Coments”)
,等等
我不确定正确的方法是什么,特别是最后一部分('%Comments'
)。确定您可以这样做:
comments_number(pll__('No Comments'), pll__('1 Comment'), pll__('% Comments'));
什么代表pll功能?这是干什么的?@Matei Mihai这就像是
\uuuuuu()代码>