Php Html表单传递输入复选框变量,不带点
我有接线问题 我的表单中有这个输入Php Html表单传递输入复选框变量,不带点,php,html,forms,Php,Html,Forms,我有接线问题 我的表单中有这个输入 <form action="..." method="post"> <div class="radio"> <input class="check-with-label" type="checkbox" id="c1-img0" name="img;http://img01.cp.aliimg.com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868
<form action="..." method="post">
<div class="radio">
<input class="check-with-label" type="checkbox" id="c1-img0" name="img;http://img01.cp.aliimg.com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868057.jpg">
<label class="label-for-check" for="c1-img0"><img src="http://img01.cp.aliimg.com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868057.jpg"></label>
</div>
</form>
就像你们看到的,我在PHP文件中的链接中丢失了所有的点
Orginal: img;http://img01.cp.aliimg.com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868057.jpg
Recived: img;http://img01_cp_aliimg_com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868057_jpg
您已将图像链接置于
name
属性中,而不是value
试一试
您想在这里做什么?该名称属性完全无效。我想将图像url传递到PHP文件。当我可以通过复选框选择要传递的图像时,我有一个页面。将action=“…”
更改为action=“”
,然后尝试。更改img;http://img01....
到值
并将name=“img_name”
添加到复选框中。然后您可以使用$\u POST['img\u name']
Orginal: img;http://img01.cp.aliimg.com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868057.jpg
Recived: img;http://img01_cp_aliimg_com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868057_jpg
<form action="" method="post">
<div class="radio">
<input class="check-with-label" type="checkbox" id="c1-img0" name="image" value="img;http://img01.cp.aliimg.com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868057.jpg">
<label class="label-for-check" for="c1-img0"><img src="http://img01.cp.aliimg.com/bao/uploaded/i1/1610868057/T25iVOXaNeXXXXXXXX_!!1610868057.jpg"></label>
</div>
<input type="submit" value="submit">
</form>
<?php
var_dump($_POST);
?>