Php 从AWS S3上传获取json

我正在结合使用将文件上载到S3。我的目标是获取AWS存储的文件名。如果我上传foo.mov十次，S3会将其命名为foo.mov、foo（1）.mov、foo（2）.mov等等。成功上传后，我在控制台中收到来自以下方法的JSON字符串响应：

protected function generate_response($content, $print_response = true) {
    if ($print_response) {
        $json = json_encode($content);
        $redirect = isset($_REQUEST['redirect']) ?
            stripslashes($_REQUEST['redirect']) : null;
        if ($redirect) {
            $this->header('Location: '.sprintf($redirect, rawurlencode($json)));
            return;
        }
        $this->head();
        if ($this->get_server_var('HTTP_CONTENT_RANGE')) {
            $files = isset($content[$this->options['param_name']]) ?
                $content[$this->options['param_name']] : null;
            if ($files && is_array($files) && is_object($files[0]) && $files[0]->size) {
                $this->header('Range: 0-'.(
                    $this->fix_integer_overflow(intval($files[0]->size)) - 1
                ));
            }
        }
        $this->body($json);
    }
    return $content;
}



public function post($print_response = true) {
    if (isset($_REQUEST['_method']) && $_REQUEST['_method'] === 'DELETE') {
        return $this->delete($print_response);
    }
    $upload = isset($_FILES[$this->options['param_name']]) ?
        $_FILES[$this->options['param_name']] : null;
    // Parse the Content-Disposition header, if available:
    $file_name = $this->get_server_var('HTTP_CONTENT_DISPOSITION') ?
        rawurldecode(preg_replace(
            '/(^[^"]+")|("$)/',
            '',
            $this->get_server_var('HTTP_CONTENT_DISPOSITION')
        )) : null;
    // Parse the Content-Range header, which has the following form:
    // Content-Range: bytes 0-524287/2000000
    $content_range = $this->get_server_var('HTTP_CONTENT_RANGE') ?
        preg_split('/[^0-9]+/', $this->get_server_var('HTTP_CONTENT_RANGE')) : null;
    $size =  $content_range ? $content_range[3] : null;
    $files = array();
    if ($upload && is_array($upload['tmp_name'])) {
        // param_name is an array identifier like "files[]",
        // $_FILES is a multi-dimensional array:
        foreach ($upload['tmp_name'] as $index => $value) {
            $files[] = $this->handle_file_upload(
                $upload['tmp_name'][$index],
                $file_name ? $file_name : $upload['name'][$index],
                $size ? $size : $upload['size'][$index],
                $upload['type'][$index],
                $upload['error'][$index],
                $index,
                $content_range
            );
        }
    } else {
        if( isset($_POST['fileSourceChooser']) && $_POST['fileSourceChooser']=='dropbox' ){

            //http://justinvincent.com/page/1087/how-to-get-the-mime-type-of-a-remote-file-in-php-with-redirects
            function get_url_mime_type($url){
                $ch = curl_init($url);
                curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
                curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
                curl_setopt($ch, CURLOPT_HEADER, 1);
                curl_setopt($ch, CURLOPT_NOBODY, 1);
                curl_exec($ch);
                return curl_getinfo($ch, CURLINFO_CONTENT_TYPE);
            }
                $upload=$_POST['files']; ////if just a regular post
                $upload['parse_url']=parse_url($upload['link']);
                $upload['url']='https://dl.dropboxusercontent.com'.$upload['parse_url']['path'];
                    $files[] = $this->handle_file_upload(
                        $upload['url'],
                        $file_name ? $file_name : $upload['name'],
                        $size ? $size : $upload['bytes'],
                        get_url_mime_type($upload['url']), 
                        "", 
                        null, null,
                        $content_range
                    );  

                    file_put_contents(
                        $this->options['upload_dir'].'thumbnail/'.$upload['name'],
                        fopen($upload['thumbnail'], 'r'),
                        FILE_APPEND //$append_file ? FILE_APPEND : 0
                    );                        
        }
        else{
            // param_name is a single object identifier like "file",
            // $_FILES is a one-dimensional array:
            $files[] = $this->handle_file_upload(
                isset($upload['tmp_name']) ? $upload['tmp_name'] : null,
                $file_name ? $file_name : (isset($upload['name']) ?
                        $upload['name'] : null),
                $size ? $size : (isset($upload['size']) ?
                        $upload['size'] : $this->get_server_var('CONTENT_LENGTH')),
                isset($upload['type']) ?
                        $upload['type'] : $this->get_server_var('CONTENT_TYPE'),
                isset($upload['error']) ? $upload['error'] : null,
                null,
                $content_range
            );                
        }
    }

    $AWSresponse = $this->generate_response(
        array($this->options['param_name'] => $files),
        $print_response
    );

    return $AWSresponse;
}

该响应如下所示：

{"files":[{"name":"foo (51).mov","size":1202952,"type":"video\/quicktime","url":"https:\/\/me.s3.amazonaws.com\/bucket\/foo%20%2851%29.mov","deleteUrl":"https:\/\/myurl.com\/folder\/path\/?file=foo%20%2851%29.mov&_method=DELETE","deleteType":"POST"}]}

如何从UploadHandler类外部访问此信息？我想我可以尝试在post方法（名为AWSresponse）中设置一个变量，将其设置为这个值，但这不起作用

该类通过以下方式执行：

require('UploadHandler.php');
$upload_handler = new UploadHandler();

我希望能够这样做（这不起作用）：

---

如果我上传foo.mov十次，S3将命名为。。。S3不命名（或重命名）任何东西。S3中对象的名称是代码发送的名称。True。除非文件名与bucket中的另一个文件名匹配。不，这是不正确的。如果名称与另一个对象匹配，S3没有行为不同的概念。在这种情况下，旧对象只是被覆盖。（如果启用了bucket版本控制，则旧版本不会被销毁，但它只能通过不透明的版本标识符访问，即使这样名称也不会更改。）如果文件的名称不同，S3绝对不会这样做。。。无论你用什么代码上传文件，都必须这样做。我坚持更正！我以为是S3——我错过了重写。但是第二个问题仍然代表着从uploadhandler中获取名称：当类通过

$upload\u handler:：$AWSresponse

显示空值时，如何访问类中的变量，但是如果我在方法中回显$AWSresponse变量，它就有内容了？

require('UploadHandler.php');
$upload_handler = new UploadHandler();
$response = $upload_handler::$AWSresponse;