PHP Mysql-使用子类别循环生成类别

正在寻求更好的PHP代码的帮助，该代码允许我生成带有子类别的类别列表，但要跨三列打印

首先，仅显示表数据演示表-尽管表名和列名正确：

--- TABLE NAME = walkthroughs ---

---------------------------------------------------------------
| id  | name                  | url           | cluster       |
---------------------------------------------------------------
|  1  | A Room with a View    | http://...    | Happyville    |
|  2  | An Outdoor Tower      | http://...    | Happyville    |
|  3  | An Old Cottage        | http://...    | Happyville    |
|  4  | Town Hall             | http://...    | Misty Vale    |
|  5  | Cathedral             | http://...    | Misty Vale    |
|  6  | Babbling Brook        | http://...    | Old Forest    |
|  7  | The Lonely Flower     | http://...    | Old Forest    |
|  8  | The Hollow Tree       | http://...    | Old Forest    |
|  9  | The Secret Garden     | http://...    | Old Forest    |
| 10  | The Forgotten Corale  | http://...    | Open Plains   |
| 11  | Echo Caverns          | http://...    | Mountains     |
| 12  | The Forgotten Corale  | http://...    | Mountains     |
---------------------------------------------------------------

我用PHP代码创建了一个“集群”类别，并在下面列出了相关的名称和URL。虽然很凌乱，但却很管用！此代码的HTML输出全部在1列中

--- HTML OUTPUT ---

<h2>Happyville</h2>
<a href="url"> A Room with a View </a>
<a href="url"> An Outdoor Tower </a>
<a href="url"> An Old Cottage </a>
<br>
<h2>Misty Vale</h2>
<a href="url"> Town Hall </a>
<a href="url"> Cathedral </a>
<br>
<h2>Old Forest</h2>
<a href="url"> Babbling Brook </a>
<a href="url"> The Lonely Flower </a>
<a href="url"> The Hollow Tree </a>
<a href="url"> The Secret Garden </a>
<br>
<h2>Open Plains</h2>
<a href="url"> Babbling Brook </a>
<br>
<h2>Mountains</h2>
<a href="url"> Echo Caverns </a>
<a href="url"> The Forgotton Corale </a>

我正在寻找PHP for Mysql的帮助：

因此，结果按“群集”字段分组， 首先打印“群集”字段的唯一值，然后打印该值的所有“名称”和“url”值， PHP/Mysql计数，可用于将结果分成3列。 最佳HTML输出如下所示

--- HTML OUTPUT ---
<div id="col-1">
  <h2>Happyville</div>
  <a href="url"> A Room with a View </a>
  <a href="url"> An Outdoor Tower </a>
  <a href="url"> An Old Cottage </a>
  <br>
  <h2>Misty Vale</h2>
  <a href="url"> Town Hall </a>
  <a href="url"> Cathedral </a>
  <br>
<div>
<div id="col-2">
  <h2>Old Forest</h2>
  <a href="url"> Babbling Brook </a>
  <a href="url"> The Lonely Flower </a>
  <a href="url"> The Hollow Tree </a>
  <a href="url"> The Secret Garden </a>
  <br>
  <h2>Open Plains</h2>
  <a href="url"> Babbling Brook </a>
  <br>
</div>
<div id="col-3">  
  <h2>Mountains</h2>
  <a href="url"> Echo Caverns </a>
  <a href="url"> The Forgotton Corale </a>
  <br>
</div>

这是我一直在使用的当前PHP，我知道它很混乱，例如，我不确定是否使用数组，虽然它可以将结果分成3列，但它会打印一个标题和第一个值，然后任何进一步的结果都会出现在下一列中，或者根本不会出现在第3列中

这个问题的一个活生生的例子是@yes，这是一个极客的MMO页面

请注意，在实时示例中，“集群”字段的名称为“集群”或“活动”。我在这里简化了名字，使生活更轻松

--- CURRENT PHP ---
<?php
include("../php/lotrodb.php");

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$queryc="SELECT * FROM walkthroughs ORDER BY cluster ASC";
$queryd="SELECT cluster,COUNT(DISTINCT(cluster)) FROM walkthroughs GROUP BY cluster";
$resultc=mysql_query($queryc);
$resultd=mysql_query($queryd);

$numc=mysql_numrows($resultc);
$numd=mysql_numrows($resultd); // used to count the number of unique values for the 'cluster' field

mysql_close();

$i=0; //$i = counter used to count queryc values 
$j=0; //$j = counter used to print out <h2>'cluster'</h2> heading

$x=0;         //$x = counter used to count queryd values
$y=($numd/3); //$y = 1/3rd of $numd - used to close a column and start a new column
$z=$y*2;      //$z = 2/3rds of $numd - used to close a column and start a new column

$cluster_current = null;
?>
   <div id="col-1">
<?php
while ($x < $y) {

$name=mysql_result($resultc,$i,"name");
$url=mysql_result($resultc,$i,"url");
$cluster=mysql_result($resultc,$i,"cluster");

  if ($cluster != $cluster_current) {
  $x=$x+1;
?>
</p>
<br>
<h2><?php echo $cluster; ?> Cluster</h2>
<p>
<?php
}
?>
<a href="<?php  echo $url; ?>" class="fade"><?php  echo $name; ?></a><br>
<?php
$i=$i+1;
$cluster_current=mysql_result($resultc,$j,"cluster");
$j=$j+1;
}
?>
   </div>
   <div id="col-2">
<?php
while ($x < $z) {

$name=mysql_result($resultc,$i,"name");
$url=mysql_result($resultc,$i,"url");
$cluster=mysql_result($resultc,$i,"cluster");

  if ($cluster != $cluster_current) {
  $x=$x+1;
?>
</p>
<br>
<h2><?php echo $cluster; ?> Cluster</h2>
<p>
<?php
}
?>
<a href="<?php  echo $url; ?>" class="fade"><?php  echo $name; ?></a><br>
<?php
$i=$i+1;
$cluster_current=mysql_result($resultc,$j,"cluster");
$j=$j+1;
}
?>
   </div>
   <div id="col-3">
<?php
while ($x < $numd) {

$name=mysql_result($resultc,$i,"name");
$url=mysql_result($resultc,$i,"url");
$cluster=mysql_result($resultc,$i,"cluster");

  if ($cluster != $cluster_current) {
$x=$x+1;
?>
</p>
<br>
<h2><?php echo $cluster; ?> Cluster</h2>
<p>
<?php
}
?>
<a href="<?php  echo $url; ?>" class="fade"><?php  echo $name; ?></a><br>
<?php
$i=$i+1;
$cluster_current=mysql_result($resultc,$j,"cluster");
$j=$j+1;
}
?>
</div>

---

我对PHP不是很熟悉，但我知道关联数组在字典中存在。这足以解决你的问题

首先，我将使用and执行此查询：

选择群集， 组_CONCAT 海螺 AS块 来自演练 分组

---

检索完后，将查询响应放入dictionary cluster=>块中，然后您可以迭代整个集群，只需在页面的适当位置回显HTML块。

我很欣赏这个方向。在查看PHP数组链接、一两个sql数组示例、使用您的查询并消除每个块结果之间的逗号后，问题已经解决。@user2901346如果我的答案对您有帮助，您可以将其标记为正确答案。