Php 根据不同的按钮提交动态获取数据

我有3个按钮要提交。比如说按钮A，B，C。 每次按下按钮都会根据按下的按钮从数据库中获取数据。但数据的模板是相同的

我的问题是，是否可以动态更改查询。尤其是查询中的WHERE字段

$sql = "SELECT Name FROM DevicesList WHERE Device='A' ";

我想要的是，根据按钮的按下，零件应该在哪里更改

//my forms are as follows
    <div class="button_style1">
      <form action="displayData.php" method="get" target="_blank">
        <input type="submit" id ="mybutton1" value="A" />
      </form>
    </div>

    <div class="button_style2">
      <form action="displayData.php" method="get" target="_blank">
        <input type="submit" id ="mybutton2" value="B" />
      </form>
    </div>


    <div class="button_style3">
      <form action="displayData.php" method="get" target="_blank">
        <input type="submit" id ="mybutton3" value="C" />
      </form>
    </div>

//I am trying to avoid creating different pages for each button press. Just one page (displayData.php) but with different data based on button press.

//我的表格如下
//我试图避免为每次按下按钮创建不同的页面。只需一个页面（displayData.php），但根据按钮的按下情况使用不同的数据。

您可以使用隐藏字段传递一些数据

例如：

<div class="button_style1">
  <form action="displayData.php" method="get" target="_blank">
    <input type="hidden" name="MyHiddenData" value="A">
    <input type="submit" id ="mybutton1" value="A" />
  </form>
</div>

<div class="button_style2">
  <form action="displayData.php" method="get" target="_blank">
    <input type="hidden" name="MyHiddenData" value="B">
    <input type="submit" id ="mybutton2" value="B" />
  </form>
</div>


<div class="button_style3">
  <form action="displayData.php" method="get" target="_blank">
    <input type="hidden" name="MyHiddenData" value="C">
    <input type="submit" id ="mybutton3" value="C" />
  </form>
</div>

---

是的，你绝对能做到

为每个元素指定相同的名称：

在发布的表单中，获取提交的按钮：

if (isset($_POST['submit')) {
 if ($_POST['submit']) {
  $var = mysqli_real_escape_string($_POST['submit']);
  $sql = "SELECT Name FROM DevicesList WHERE Device='" . $var . "'";
 }
}

一次，只有一个提交按钮将提交

---

因此，您每次都会得到submit按钮的名称，这就是您在SQL中比较的内容。

您可以像下面这样做

<div class="button_style1">
    <form action="displayData.php" method="get"  target="_blank">
        <input type="submit" name="submit" id ="mybutton1" value="A" />
    </form>
</div>

<div class="button_style2">
    <form action="displayData.php" method="get" target="_blank">
        <input type="submit" name="submit" id ="mybutton2" value="B" />
    </form>
</div>


<div class="button_style3">
    <form action="displayData.php" method="get" target="_blank">
        <input type="submit" name="submit" id ="mybutton3" value="C" />
    </form>
</div>

---

如何更改查询中的WHERE字段？比如WHERE Device=“.MyDevice”就是这样的。您希望将prepared语句与或或用于查询数据库的任何语句一起使用，以避免对prepared语句懒惰。为什么不使用按钮的值（如果您为所有按钮指定了相同的名称）-如果在php中按下按钮，它不是与表单一起发布吗？这很容易受到SQL注入的攻击。对SQL注入不安全

<div class="button_style1">
    <form action="displayData.php" method="get"  target="_blank">
        <input type="submit" name="submit" id ="mybutton1" value="A" />
    </form>
</div>

<div class="button_style2">
    <form action="displayData.php" method="get" target="_blank">
        <input type="submit" name="submit" id ="mybutton2" value="B" />
    </form>
</div>


<div class="button_style3">
    <form action="displayData.php" method="get" target="_blank">
        <input type="submit" name="submit" id ="mybutton3" value="C" />
    </form>
</div>

if (isset($_GET['submit']) && in_array($_GET['submit'], array('A', 'B', 'C'))) {
    $variable = mysqli_real_escape_string($con, $_GET['submit']); //$con - database connection object
    $sql = "SELECT Name FROM DevicesList WHERE Device='" + $variable + "' ";
}