Php Laravel雄辩地连接2个表
这些是我的模型:Php Laravel雄辩地连接2个表,php,join,laravel-4,eloquent,Php,Join,Laravel 4,Eloquent,这些是我的模型: class Branch extends Eloquent { protected $table = 'tb_branch'; public function faculty() { return $this->hasMany('Faculty'); } } class Faculty extends Eloquent { protected $table = 'tb_faculty'; publ
class Branch extends Eloquent {
protected $table = 'tb_branch';
public function faculty()
{
return $this->hasMany('Faculty');
}
}
class Faculty extends Eloquent {
protected $table = 'tb_faculty';
public function branch()
{
return $this->belongsTo('Branch');
}
}
在分支表中,我设置了一个外键为user\u id的列,该列链接到users表
在faculty表中,我设置了一个带有外键branch
的列,该列链接到带有columnname
的branch表
现在我需要根据当前登录的用户检索教员数据(带有Eloquent)
我想工作流程是:
- 检索当前登录用户的id
- 将该id链接到分支机构的
并检索分支机构的用户id
名称
- 将该分支机构的
链接到教员分支机构的名称
,并检索所有匹配的教员数据名称
$user_id = Sentry::getUser();
$faculty = Faculty::with('branch')->where('branch.user_id',$user->id)->get();
错误是:
“where子句”(SQL:select*from)中的未知列“branch.user_id”
tbu教员
其中分支机构
用户id
=6)
我怎样才能做到这一点与雄辩
retrieve id of currently logged in user
link that id to the branch's user_id and retrieve branch's name
link that branch's name to faculty branch's name and retrieve all matched faculty data
因此,第一种方式:
$user_id = Auth::user()->id;
$branch = Branch::where('user_id', '=', $user_id)->first();
$faculties = Faculty::where('branch_name', '=', $branch->name)->get();
第二种方式:
如果系基于名称,则:
class Branch extends Eloquent {
public function faculties() {
return Faculty::where('branch_name', '=', $this->name)->get();
/*
or do this: return $this->hasMany('Faculty', 'branch_name', 'name');
*/
}
}
然后这样做:
$user_id = Auth::user()->id;
$faculties = Branch::where('user_id', '=', $user_id)->first()->faculties;
然后在视图中:
foreach($faculties as $fac)
{
echo $fac->name.'<br />';
}
foreach($faculties作为$fac)
{
echo$fac->name.“
”;
}
谢谢,这是我的第一个解决方案,但我尝试使用join,因此查询只需一行,并最小化数据库连接。faculties函数的第二个解决方案有效return$this->hasMany('Faculty'、'branch_name'、'name')代码>。非常感谢:您还可以加入以下字段:),很高兴为您提供帮助