在PHP中获取每个月的两个日期全天
我如何在这样的数组中获得每个月两天之间的所有天数在PHP中获取每个月的两个日期全天,php,arrays,date,days,monthcalendar,Php,Arrays,Date,Days,Monthcalendar,我如何在这样的数组中获得每个月两天之间的所有天数 $dateStart = "2016/12/14"; $dateFin = "2017/04/21" [2016/12/14 - 2016/12/31] => 17 days [2017/01/01 - 2017/01/31] => 31 days [2017/02/01 - 2017/02/28] => 28 days [2017/03/01 - 2017/03/30] => 31 days [2017/04/0
$dateStart = "2016/12/14";
$dateFin = "2017/04/21"
[2016/12/14 - 2016/12/31] => 17 days
[2017/01/01 - 2017/01/31] => 31 days
[2017/02/01 - 2017/02/28] => 28 days
[2017/03/01 - 2017/03/30] => 31 days
[2017/04/01 - 2017/04/21] => 21 days
要获取两个日期的日期差(以天为单位),可以执行以下操作:
function daysDiff($d1, $d2)
{
$x1 = days($d1);
$x2 = days($d2);
if ($x1 && $x2) {
return abs($x1 - $x2);
}
}
function days(DateTime $x)
{
$y = $x->format('Y') - 1;
$days = $y * 365;
$z = (int)($y / 4);
$days += $z;
$z = (int)($y / 100);
$days -= $z;
$z = (int)($y / 400);
$days += $z;
$days += $x->format('z');
return $days;
}
$d1和$d2应该是DateTime类型,我从这里复制了这段代码:并做了一个小的修改,使用类型暗示,而不是使用get_类验证变量类型
查看演示
您可以使用function plus DateTime类:
<?php
$dateStart = new DateTime("2016/12/14");
$dateFin = new DateTime("2017/04/21");
$firstDay = $dateStart->format('Y/m/d');
$lastDay = $dateStart->format('Y/m/t');
$totalMonths = $dateStart->diff($dateFin)->m + ($dateStart->diff($dateFin)->y*12);
$result = [];
for ($i = 0; $i <= $totalMonths; $i++)
{
if ($i != 0){
$dateStart->modify('first day of next month');
$firstDay = $dateStart->format('Y/m/d');
$dateStart->modify('last day of month');
$lastDay = $dateStart->format('Y/m/t');
}
$nextDate = explode('/', $firstDay);
$totalDays = cal_days_in_month(CAL_GREGORIAN, $nextDate[1], $nextDate[2]);
if ($i == 0){
$totalDays -= $dateStart->format('d');
} else if ($i == $totalMonths) {
$totalDays = $dateFin->format('d');
}
$result["$firstDay - $lastDay"] = $totalDays;
}
var_dump($result);
请根据上述描述尝试执行以下代码片段作为解决方案
$start_date = new DateTime('2016/12/14');
$start_date=$start_date->modify('+1 day');
$end_date = new DateTime('2017/04/21');
$end_date = $end_date->modify('+1 day');
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($start_date, $interval ,$end_date);
$month_days=array();
foreach($daterange as $date)
{
$date_month=$date->format('m');
$month_days[$date_month][]=$date->format('Y/m/d');
}
$result=array();
foreach($month_days as $days)
{
$begin=reset($days);
$end=end($days);
$result[$begin.'-'.$end]=count($days);
}
echo '<pre>';
print_r($result);
$start_date=新日期时间('2016/12/14');
$start_date=$start_date->修改(“+1天”);
$end_date=新日期时间('2017/04/21');
$end_date=$end_date->modify(“+1天”);
$interval=新的日期间隔('P1D');
$daterange=新的日期周期($start\u date,$interval,$end\u date);
$month_days=array();
foreach($daterange作为$date)
{
$date\u month=$date->format('m');
$month\u days[$date\u month][]=$date->format('Y/m/d');
}
$result=array();
foreach($month\u days作为$days)
{
$begin=重置(天);
$end=结束($days);
$result[$begin.'-'.$end]=计数($days);
}
回声';
打印(结果);
我会改进,等一会儿:)请检查我的改进,我想我必须再增加一次循环,所以我必须在总共几个月内应用+1才能得到准确的结果。
$dateStart = new DateTime("2016/12/14");
$dateFin = new DateTime("2017/04/21");
$totalMonths = $dateStart->diff($dateFin)->m + ($dateStart->diff($dateFin)->y*12);
$result = [];
for ($i = 0; $i <= $totalMonths; $i++)
{
if ($i != 0){
$obj = $dateStart->modify('first day of next month');
}
$firstDay = $dateStart->format('Y/m/d');
if ($i == $totalMonths){
$lastDay = $dateFin->format('Y/m/d');
} else {
$lastDay = $dateStart->format('Y/m/t');
}
$firstDayObj = strtotime($firstDay);
$lastDayObj = strtotime($lastDay);
$totalDays = (int) ceil(($lastDayObj - $firstDayObj) / 86400);
$totalDays = ((int) $dateStart->format('d') == 1) ? $totalDays + 1 : $totalDays;
$result["$firstDay - $lastDay"] = $totalDays;
}
var_dump($result);
//array(5) { ["2016/12/14 - 2016/12/31"]=> int(17) ["2017/01/01 - 2017/01/31"]=> int(31) ["2017/02/01 - 2017/02/28"]=> int(28) ["2017/03/01 - 2017/03/31"]=> int(31) ["2017/04/01 - 2017/04/21"]=> int(21) }
$start_date = new DateTime('2016/12/14');
$start_date=$start_date->modify('+1 day');
$end_date = new DateTime('2017/04/21');
$end_date = $end_date->modify('+1 day');
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($start_date, $interval ,$end_date);
$month_days=array();
foreach($daterange as $date)
{
$date_month=$date->format('m');
$month_days[$date_month][]=$date->format('Y/m/d');
}
$result=array();
foreach($month_days as $days)
{
$begin=reset($days);
$end=end($days);
$result[$begin.'-'.$end]=count($days);
}
echo '<pre>';
print_r($result);