我的CSV附件是空的!PHP

我的CSV附件是空的!PHP,php,mysql,excel,email,csv,Php,Mysql,Excel,Email,Csv,我试图从数据库中获取数据,并将其显示在CSV文件中,该文件可以下载并通过电子邮件发送给他人。我已经设法使可下载的文件工作,它显示了所有正确的数据。它还将CSV文件发送给必要的人员,但该CSV文件为空且其中未显示任何数据 这是我的密码: $myroot = "../../"; include($myroot . "inc/functions.php"); // output headers so that the file is downloaded rather

我试图从数据库中获取数据,并将其显示在CSV文件中,该文件可以下载并通过电子邮件发送给他人。我已经设法使可下载的文件工作,它显示了所有正确的数据。它还将CSV文件发送给必要的人员,但该CSV文件为空且其中未显示任何数据

这是我的密码:

    $myroot = "../../";
    include($myroot . "inc/functions.php");
        // output headers so that the file is downloaded rather than displayed
        header('Content-Type: text/csv; charset=utf-8');
        header('Content-Disposition: attachment; filename=surveys.csv');
        $output = fopen('php://output', 'w');
// Create CSV file
fputcsv($output, array('Name', 'Branch', 'Website','Company', 'Question1', 'Question2', 'Question3', 'Question4', 'Question5'));

$mysql_connection = db_connect_enhanced('*****','*****','*****','*****');
$query='SELECT * FROM *****.*****';
$surveys = db_query_into_array_enhanced($mysql_connection, $query);
$count = count($surveys);
$data = array();
    for($i=0; $i<=$count; $i++){
    $data[] = array($surveys[$i]['FeedbackName'], $surveys[$i]['BranchName'], $surveys[$i]['FeedbackWebsite'], $surveys[$i]['FeedbackCompany'], $surveys[$i]['Question1'], $surveys[$i]['Question2'], $surveys[$i]['Question3'], $surveys[$i]['Question4'], $surveys[$i]['Question5']);  
}

foreach( $data as $row )  
{  
    fputcsv($output, $row, ',', '"');  
}  
fclose($output);  

$encoded = chunk_split(base64_encode($output));

// create the email and send it off

$subject = "File you requested from RRWH.com";
$from = "*****@*****.com";
$headers = 'MIME-Version: 1.0' . "\n";
$headers .= 'Content-Type: multipart/mixed;
   boundary="----=_NextPart_001_0011_1234ABCD.4321FDAC"' . "\n";

$message = '

This is a multi-part message in MIME format.

------=_NextPart_001_0011_1234ABCD.4321FDAC
Content-Type: text/plain;
       charset="us-ascii"
Content-Transfer-Encoding: 7bit

Hello

We have attached for you the PHP script that you requested from http://rrwh.com/scripts.php
as a zip file.

Regards

------=_NextPart_001_0011_1234ABCD.4321FDAC
Content-Type: application/octet-stream;  name="';

$message .= "surveys.csv";
$message .= '"
Content-Transfer-Encoding: base64
Content-Disposition: attachment; filename="';
$message .= "surveys.csv";
$message .= '"

';
$message .= $encoded;
$message .= '

------=_NextPart_001_0011_1234ABCD.4321FDAC--

';
mail("*****@*****.com", $subject, $message, $headers, "-f$from");
$myroot=“../../”;
包括($myroot.inc/functions.php”);
//输出标题,以便下载而不是显示文件
标题('Content-Type:text/csv;charset=utf-8');
标题('Content-Disposition:attachment;filename=surveys.csv');
$output=fopen('php://output","w",;
//创建CSV文件
fputcsv($output,array('Name','Branch','Website','Company','Question1','Question2','Question3','Question4','Question5');
$mysql_connection=db_connect_增强(“****”、“****”、“****”、“****”、“****”);
$query='SELECT*FROM***********';
$surveys=db\u query\u into\u array\u enhanced($mysql\u connection,$query);
$count=计数(调查);
$data=array();
for($i=0;$i
base64\u encode()
希望参数是字符串,您给它一个(闭合的)资源。 尝试将资源读入字符串,或在写入资源时使用
file\u get\u contents
或构建字符串

更新:

试着替换

foreach( $data as $row )  
{  
    fputcsv($output, $row, ',', '"');  
} 
fclose($output);  
$encoded = chunk_split(base64_encode($output));


这样,写入输出的所有内容都会写入一个新变量(
$myoutput
)。因为这是一个字符串,所以可以将其与
base64\u encode()一起使用

如果可能的话,我建议使用一个库来处理邮件,SwiftMailer会让这项任务更简单。我觉得我的代码已经差不多完成了。我真的很想保留它,而不是废弃它。我不明白。我如何将资源读入字符串?或者如何使用文件内容?谢谢!!!那个小chan通用电气已经修复了它,现在它工作了:48个小时的废话,你很容易就解决了,谢谢。请记住,我会认为这是一个“黑客”。虽然不雅致,但很管用。。。大多数时候。我会…还有一个小问题…CSV文件现在充满了数据,这很好…但是列标题不在顶部(名称、分支、网站等)。为什么它们没有进入CSV文件?文件中只显示字符串
$myoutput
。我更新了我的答案。
$myoutput = '"Name","Branch","Website","Company","Question1","Question2","Question3","Question4","Question5"';
foreach( $data as $row )  
{  
    $myoutput .= "\"".implode('","',$row)."\"\n";
    fputcsv($output, $row, ',', '"');  
} 
fclose($output);  
$encoded = chunk_split(base64_encode($myoutput));