Php 如何在Laravel中使用insertGetId进行存储以使用不同的ID进行不同的插入

Php 如何在Laravel中使用insertGetId进行存储以使用不同的ID进行不同的插入,php,mysql,laravel,migration,Php,Mysql,Laravel,Migration,在数据库中,它是这样插入的: *Migration* Schema::create('test', function (Blueprint $table) { $table->integer('id')->unsigned(); $table->unsignedBigInteger('user_id'); $table->foreign('user_id')->references('

在数据库中,它是这样插入的:

*Migration*   
  Schema::create('test', function (Blueprint $table) {
            $table->integer('id')->unsigned();
            $table->unsignedBigInteger('user_id');
            $table->foreign('user_id')->references('id')->on('users');
        });

*arrary to be inserted*
    $myarray = [ ['user_id' => 1],['user_id' => 2], ['user_id' => 2], ];  



foreach ($myarray as $key => $value) {
        $id[] = Users::insertGetId(
            ['user_id' => $value['user_id']]
        );
    }
id  user_id
0   1
0   1
0   2

0   1
0   1
0   2
但是当我第二次存储时,它又像这样存储了

id  user_id
0   1
0   1
0   2
ID被复制,我想使用两个唯一的ID,如下所示:

*Migration*   
  Schema::create('test', function (Blueprint $table) {
            $table->integer('id')->unsigned();
            $table->unsignedBigInteger('user_id');
            $table->foreign('user_id')->references('id')->on('users');
        });

*arrary to be inserted*
    $myarray = [ ['user_id' => 1],['user_id' => 2], ['user_id' => 2], ];  



foreach ($myarray as $key => $value) {
        $id[] = Users::insertGetId(
            ['user_id' => $value['user_id']]
        );
    }
id  user_id
0   1
0   1
0   2

0   1
0   1
0   2