在PHP中对数组的一部分进行排序
我有这个阵列:在PHP中对数组的一部分进行排序,php,arrays,Php,Arrays,我有这个阵列: array ('project'=>'My project','leader'=>'Michael Phepps','partner1'=>'John Campbell','partner2'=>'Phillip Prescott','agepartner1'=>25, 'agepartner2'=>'44', 'budget'=>'80000'); 数组是不同表中某些查询的结果: 项目表字段:项目、领导、预算。 合作伙伴字段:合作伙伴
array ('project'=>'My project','leader'=>'Michael Phepps','partner1'=>'John Campbell','partner2'=>'Phillip Prescott','agepartner1'=>25, 'agepartner2'=>'44', 'budget'=>'80000');
数组是不同表中某些查询的结果:
项目表字段:项目、领导、预算。
合作伙伴字段:合作伙伴、年龄
数组的顺序由用户定义,执行方式如下:
foreach ($userarray as $field) {loadField($field)};
由于该操作是针对每个字段的,因此我在“partner1”之后获得“partner2”,但我需要在“partner1”之后获得“agepartner1”,因为在这之后它们将显示在html表中
我可以得到任何建议:
array ('project'=>'My project','leader'=>'Michael Phepps','partner1'=>'John Campbell', 'agepartner1'=>25, 'partner2'=>'Phillip Prescott', 'agepartner2'=>'44', 'budget'=>'80000');
虽然可能不是你想要的答案,但我认为有更好的方法来处理你的情况:
$data = array('key1' => 'is', 'key2' => 'test', 'key3' => 'This');
$order = array('key3', 'key1', 'key2');
foreach($order as $key){
print_r($data[$key]);
}
输出:
This is test.
Keys:
array(7) {
[0]=>
string(7) "project"
[1]=>
string(6) "leader"
[2]=>
string(8) "partner1"
[3]=>
string(8) "partner2"
[4]=>
string(11) "agepartner1"
[5]=>
string(11) "agepartner2"
[6]=>
string(6) "budget"
}
Categories:
array(5) {
["project"]=>
array(1) {
[0]=>
string(7) "project"
}
["leader"]=>
array(1) {
[0]=>
string(6) "leader"
}
[1]=>
array(2) {
[0]=>
string(8) "partner1"
[1]=>
string(11) "agepartner1"
}
[2]=>
array(2) {
[0]=>
string(8) "partner2"
[1]=>
string(11) "agepartner2"
}
["budget"]=>
array(1) {
[0]=>
string(6) "budget"
}
}
Groups:
array(3) {
[0]=>
array(1) {
[1]=>
array(2) {
[0]=>
array(1) {
[0]=>
string(7) "project"
}
[1]=>
array(1) {
[0]=>
string(6) "leader"
}
}
}
[1]=>
array(1) {
[2]=>
array(2) {
[0]=>
array(2) {
[0]=>
string(8) "partner1"
[1]=>
string(11) "agepartner1"
}
[1]=>
array(2) {
[0]=>
string(8) "partner2"
[1]=>
string(11) "agepartner2"
}
}
}
[2]=>
array(1) {
[1]=>
array(1) {
[0]=>
array(1) {
[0]=>
string(6) "budget"
}
}
}
}
Un-Grouped:
array(7) {
[0]=>
string(7) "project"
[1]=>
string(6) "leader"
[2]=>
string(8) "partner1"
[3]=>
string(11) "agepartner1"
[4]=>
string(8) "partner2"
[5]=>
string(11) "agepartner2"
[6]=>
string(6) "budget"
}
Sorted:
array(7) {
["project"]=>
string(10) "My project"
["leader"]=>
string(14) "Michael Phepps"
["partner1"]=>
string(13) "John Campbell"
["agepartner1"]=>
int(25)
["partner2"]=>
string(16) "Phillip Prescott"
["agepartner2"]=>
string(2) "44"
["budget"]=>
string(5) "80000"
}
因此,根据您的数据:
$userarray = array ('project'=>'My project',
'leader'=>'Michael Phepps',
'partner1'=>'John Campbell',
'partner2'=>'Phillip Prescott',
'agepartner1'=>25,
'agepartner2'=>'44',
'budget'=>'80000');
$order = array('project',
'leader',
'partner1',
'agepartner1',
'partner2',
'agepartner2',
'budget');
foreach($order as $field) {
loadField($userarray[$field]);
}
不能直接订购数组的一部分。您只能将数组划分为要排序的部分,然后对这些部分进行排序,然后对数组数据应用该排序。因为你也不能改变按键的位置。正如蒂姆·莱特尔建议的那样,拿到钥匙,对它们进行排序,然后你就有了解决方案。这稍微减少了一点问题 自然有解决办法。但是,请记住,您的数据结构很难排序。我做了以下工作:
- 拿到钥匙
- 对键进行分类:如果不包含数字,则类别为键本身;如果包含数字,则类别为数字
- 根据类别将所有关键帧划分为组。这意味着,每次类别更改时,都会有一个新的组开始:
ALPHA,DIGIT,ALPHA
- 打通了所有的小组并处理了他们<代码>数字组可能需要排序,因此我对它们进行了排序(例如,如果
位于agepartner
之前,我只进行了a-z排序+反向排序)partner
- 再次将所有部分展平为键阵列。键排序完成
- 根据新的键顺序和原始数组中的值创建一个
数组$sorted
ksort
)对每个数字
组进行排序。由于您的数据结构如此复杂,下面的代码示例包含调试输出和一些注释,因此您至少可以更轻松地浏览和使用它:
$array = array ('project'=>'My project','leader'=>'Michael Phepps','partner1'=>'John Campbell','partner2'=>'Phillip Prescott','agepartner1'=>25, 'agepartner2'=>'44', 'budget'=>'80000');
// reduce the problem: If we can sort the keys, we have the solution.
$keys = array_keys($array);
echo "Keys:\n";
var_dump($keys);
// categorize keys: alpha-only or alpha and digits at the end
$categories = array();
foreach($keys as $key)
{
$r = preg_match('/^([a-z]+)(\d*)$/', $key, $matches);
assert('$r !== FALSE');
list(,$alpha, $digits) = $matches;
$category = $digits ? $digits : $alpha;
$categories[$category][] = $key;
}
echo "Categories:\n";
var_dump($categories);
// group categories together in their order: ALPHA blocks and DIGIT blocks
define('GROUP_ALPHA', 1);
define('GROUP_DIGIT', 2);
$last = GROUP_ALPHA;
$group = array(); // start with an empty group to add to, pointer
$groups = array(array(GROUP_ALPHA => &$group));
foreach($categories as $vkey => $category)
{
$current = is_int($vkey) ? GROUP_DIGIT : GROUP_ALPHA;
if ($current != $last)
{
// add new group
unset($group);
$group = array();
$groups[] = array($current => &$group);
}
$group[] = $category;
$last = $current;
}
unset($group); // remove pointer
echo "Groups:\n";
var_dump($groups);
// sort and flatten groups
$ungroup = array();
foreach($groups as $type => $group)
{
if ($type == GROUP_DIGIT)
{
// if digit groups need to be sorted: partner, agepartner
foreach($group as &$items)
{
sort($items);
array_reverse($items);
unset($items);
}
}
// flatten the group
$group = call_user_func_array('array_merge', $group);
$group = call_user_func_array('array_merge', $group);
$ungroup = array_merge($ungroup, $group);
}
echo "Un-Grouped:\n";
var_dump($ungroup);
// solve
$sorted = array();
foreach($ungroup as $key)
{
$sorted[$key] = $array[$key];
}
echo "Sorted:\n";
var_dump($sorted);
输出:
This is test.
Keys:
array(7) {
[0]=>
string(7) "project"
[1]=>
string(6) "leader"
[2]=>
string(8) "partner1"
[3]=>
string(8) "partner2"
[4]=>
string(11) "agepartner1"
[5]=>
string(11) "agepartner2"
[6]=>
string(6) "budget"
}
Categories:
array(5) {
["project"]=>
array(1) {
[0]=>
string(7) "project"
}
["leader"]=>
array(1) {
[0]=>
string(6) "leader"
}
[1]=>
array(2) {
[0]=>
string(8) "partner1"
[1]=>
string(11) "agepartner1"
}
[2]=>
array(2) {
[0]=>
string(8) "partner2"
[1]=>
string(11) "agepartner2"
}
["budget"]=>
array(1) {
[0]=>
string(6) "budget"
}
}
Groups:
array(3) {
[0]=>
array(1) {
[1]=>
array(2) {
[0]=>
array(1) {
[0]=>
string(7) "project"
}
[1]=>
array(1) {
[0]=>
string(6) "leader"
}
}
}
[1]=>
array(1) {
[2]=>
array(2) {
[0]=>
array(2) {
[0]=>
string(8) "partner1"
[1]=>
string(11) "agepartner1"
}
[1]=>
array(2) {
[0]=>
string(8) "partner2"
[1]=>
string(11) "agepartner2"
}
}
}
[2]=>
array(1) {
[1]=>
array(1) {
[0]=>
array(1) {
[0]=>
string(6) "budget"
}
}
}
}
Un-Grouped:
array(7) {
[0]=>
string(7) "project"
[1]=>
string(6) "leader"
[2]=>
string(8) "partner1"
[3]=>
string(11) "agepartner1"
[4]=>
string(8) "partner2"
[5]=>
string(11) "agepartner2"
[6]=>
string(6) "budget"
}
Sorted:
array(7) {
["project"]=>
string(10) "My project"
["leader"]=>
string(14) "Michael Phepps"
["partner1"]=>
string(13) "John Campbell"
["agepartner1"]=>
int(25)
["partner2"]=>
string(16) "Phillip Prescott"
["agepartner2"]=>
string(2) "44"
["budget"]=>
string(5) "80000"
}
可能的重复如果您只传递整个数组,并且在输出HTML的任何地方,只要回显正确的值,不是更容易吗?嗨@Tim,谢谢您的回答。你的建议很好。我的情况使练习更加复杂。我不知道每个项目会有多少合作伙伴。我在sql查询之后就知道了。然后,一旦有了结果,就可以创建order数组了。或者,与我的示例在已知字段中循环的方式类似,您可以在
partnerX
中循环,直到找到未设置的。