Php 如何修改此脚本以添加而不是增加
您的意思是对$aDoor数组的前i个元素求和 可能是这样的:Php 如何修改此脚本以添加而不是增加,php,Php,您的意思是对$aDoor数组的前i个元素求和 可能是这样的: <?php $aDoor = $_POST['formDoor']; if(empty($aDoor)) { echo("You didn't select any buildings."); } else { $N = count($aDoor); echo("You selected $N door(s): "); for($i=0; $i < $N; $
<?php
$aDoor = $_POST['formDoor'];
if(empty($aDoor))
{
echo("You didn't select any buildings.");
}
else
{
$N = count($aDoor);
echo("You selected $N door(s): ");
for($i=0; $i < $N; $i++)
{
echo($aDoor[$i] . " ");
}
}
?>
$sum=0;
对于($i=0;$i<$N;$i++)
{
$sum+=$aDoor[$i];
}
$total=0
对于($i=0;$i<$N;$i++)
{
$total+=$aDoor[$i];
}
echo“总计:$Total”;
找到了解决方案谢谢大家
$sum = 0;
for ( $i = 0; $i < $N; $i++ )
{
$sum += $aDoor[$i];
}
$sum = 0;
foreach($aDoor as $value){
$sum += $value;
}
echo 'Sum: ' . $sum;
<?php
$aDoor = $_POST['formDoor'];
if(empty($aDoor))
{
echo("You didn't select any buildings.");
}
else
{
$N = count($aDoor);
//echo("You selected $N door(s): ");
var $iDoors = 0;
for($i=0; $i < $N; $i++)
{
//echo($aDoor[$i] . " ");
$iDoors += $aDoor[$i];
}
echo("You selected $iDoors door(s): ");
}
?>
$total = 0
for($i=0; $i < $N; $i++)
{
$total += $aDoor[$i];
}
echo "Total: $total";