如何在php中使用正则表达式删除指定字符串之后的特定字符串？

我有一根像下面这样的线

 [Session #1: Tues May 31st - Fri June 10th (1-5:30PM)#1 only: 1pmADV] => 2
    [Session #1: Tues May 31st - Fri June 10th (1-5:30PM)#1 only: 2pmADV] => 1
    [Session #2: Tues June 14th - Fri June 24th (9-2:00PM)#1 only: 2pmADV] => 1
    [Session #1: Tues May 31st - Fri June 10th (1-5:30PM)#1 only: 1pmN/S+] => 1
    [Session #2: Tues June 14th - Fri June 24th (9-2:00PM)#1 only: 2pmN/S+] => 1
    [Session #2: Tues June 14th - Fri June 24th (9-2:00PM)#1 only: 3:30pmN/S+] => 1

我需要删除字符串“pm”后的文本，直到第一次出现“]”

比如说,

from
[Session #1: Tues May 31st - Fri June 10th (1-5:30PM)#1 only: 1pmADV] => 2
to
[Session #1: Tues May 31st - Fri June 10th (1-5:30PM)#1 only: 1pm] => 2

---

我怎样才能做到这一点呢？

如果所有字符串都是这种格式，您可以使用基本的字符串函数

$str = "[Session #1: Tues May 31st - Fri June 10th (1-5:30PM)#1 only: 1pmADV]";
$str = substr($str, 0, strpos($str, "pm") + 2);
$str .= "]";

$str=“[Session#1:5月31日星期二至6月10日星期五（下午1-5:30）#1仅限1:1pmADV]=>2”
echo preg_替换（'/（？如何：

$str = preg_replace("/(pm)[^\]]+(\])/", "$1$2", $str);

这将删除在
pm
和第一次出现的
]
之间不是
]
的所有字符

$str = preg_replace("/(pm)[^\]]+(\])/", "$1$2", $str);