Php 数组拉出没有结果
我编辑了上面没有结果的类。但是,下面的原始类会提取结果。请找个人帮忙Php 数组拉出没有结果,php,arrays,Php,Arrays,我编辑了上面没有结果的类。但是,下面的原始类会提取结果。请找个人帮忙 public function GetRoomTotalForDay($room, $date = null) { if(!isset($date)) { $date = date("Y-m-d"); } // This function is going to return the number of shoes
public function GetRoomTotalForDay($room, $date = null) {
if(!isset($date)) {
$date = date("Y-m-d");
}
// This function is going to return the number of shoes processed that day
// First of all work out which scanner number is required for the room
$scanner = $this->GetScannerNumber($room);
// Next generate the SQL
$sql = "SELECT `scanners.KordNo`, `scanners.BundleNumber`
FROM `scanners`
WHERE `scanners.Date` = '" . $date . "'
AND `scanners.Scanner` IN (";
foreach($scanner as $x) {
$sql .= $x . ",";
}
$sql .= "0);";
// And query the database
$result = mysql_query($sql);
while($row = mysql_fetch_array($result)) {
$return[] = $row;
}
// It is more complicated for Kettering, Closing & Rushden, we need to filter the list
if(in_array($room, array(3,4,5))) {
foreach($return as $x) {
$sql = "SELECT `scanners.Scanner`
FROM `scanners`
WHERE `scanners.KordNo` = " . $x['scanners.KordNo'] . "
AND `scanners.BundleNumber` = " . $x['scanner.BundleNumber'] . "
ORDER BY `scanners.Date` DESC
LIMIT 1,1;";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
// If scanner 7, it's been through bottom stock so need to find previous
if($row[0] == 7) {
$sql = "SELECT `scanners.Scanner`
FROM `scanners`
WHERE `scanners.KordNo` = " . $x['scanners.KordNo'] . "
AND `scanners.BundleNumber` = " . $x['scanners.BundleNumber'] . "
ORDER BY `scanners.Date` DESC
LIMIT 2,1;";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
}
if($row[0] == 10 && $room == 3) {
$finalReturn[] = $x;
} elseif($row[0] == 11 && $room == 4) {
$finalReturn[] = $x;
} elseif($row[0] == 15 && $room == 5) {
$finalReturn[] = $x;
}
}
$return = $finalReturn;
}
// Now we have a list of tickets, we need to query how many pairs are in each ticket
$total = 0;
foreach($return as $x) {
$sql = "SELECT `QtyIssued`
FROM `ArchiveBundle`
WHERE `ArchiveBundle.KordNo` = '" . $x['scanners.KordNo'] . "'
AND `ArchiveBundle.BundleNumber` = '" . $x['scanners.BundleNumber'] . "';";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
$total += $row[0];
}
return $total;
}
上面的类别统计生产的鞋子数量。我不得不编辑这个类,这样它就可以排除某些类型的鞋子,但出于某种原因,它似乎没有得到任何结果
更新
这是扫描器类。这就是目前的情况。我对php相当陌生,这段代码是由我的前任编写的
public function GetRoomTotalForDay($room, $date = null) {
if(!isset($date)) {
$date = date("Y-m-d");
}
// This function is going to return the number of shoes processed that day
// First of all work out which scanner number is required for the room
$scanner = $this->GetScannerNumber($room);
// Next generate the SQL
$sql = "SELECT `KordNo`, `BundleNumber`
FROM `scanners`
WHERE `Date` = '" . $date . "'
AND `Scanner` IN (";
foreach($scanner as $x) {
$sql .= $x . ",";
}
$sql .= "0);";
// And query the database
$result = mysql_query($sql);
while($row = mysql_fetch_array($result)) {
$return[] = $row;
}
// It is more complicated for Kettering, Closing & Rushden, we need to filter the list
if(in_array($room, array(3,4,5))) {
foreach($return as $x) {
$sql = "SELECT `Scanner`
FROM `scanners`
WHERE `KordNo` = " . $x['KordNo'] . "
AND `BundleNumber` = " . $x['BundleNumber'] . "
ORDER BY `Date` DESC
LIMIT 1,1;";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
// If scanner 7, it's been through bottom stock so need to find previous
if($row[0] == 7) {
$sql = "SELECT `Scanner`
FROM `scanners`
WHERE `KordNo` = " . $x['KordNo'] . "
AND `BundleNumber` = " . $x['BundleNumber'] . "
ORDER BY `Date` DESC
LIMIT 2,1;";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
}
if($row[0] == 10 && $room == 3) {
$finalReturn[] = $x;
} elseif($row[0] == 11 && $room == 4) {
$finalReturn[] = $x;
} elseif($row[0] == 15 && $room == 5) {
$finalReturn[] = $x;
}
}
$return = $finalReturn;
}
// Now we have a list of tickets, we need to query how many pairs are in each ticket
$total = 0;
foreach($return as $x) {
$sql = "SELECT `QtyIssued`
FROM `ArchiveBundle`
WHERE `KordNo` = '" . $x['KordNo'] . "'
AND `BundleNumber` = '" . $x['BundleNumber'] . "';";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
$total += $row[0];
}
return $total;
}
?>您有一个打字错误-这段代码的最后一行缺少一个字母:
<?php
class CHScanners {
var $conn;
// Constructor, connect to the database
public function __construct() {
require_once "/var/www/reporting/settings.php";
define("DAY", 86400);
if(!$this->conn = mysql_connect(DB_HOST, DB_USERNAME, DB_PASSWORD)) die(mysql_error());
if(!mysql_select_db(DB_DATABASE_NAME, $this->conn)) die(mysql_error());
}
public function ListRoomBundles($room, $date, $dateTo = null) {
// If dateTo hasn't been set, make it now
if(!isset($dateTo) or $dateTo == "") {
$dateTo = $date;
}
// Return an array with each bundle number and the quantity for each day
$scanner = $this->GetScannerNumber($room);
$sql = "SELECT * FROM `scanners` WHERE `Scanner` IN (";
foreach($scanner as $x) {
$sql .= $x . ",";
}
$sql .= "0)
AND `Date` BETWEEN '" . $date . "' AND '" . $dateTo . "'
GROUP BY `KordNo`, `BundleNumber`;";
$result = mysql_query($sql);
while($row = mysql_fetch_array($result)) {
$sql = "SELECT `BundleReference`, `QtyIssued`, `WorksOrder`
FROM `ArchiveBundle`
WHERE `KordNo` = '" . $row['KordNo'] . "'
AND `BundleNumber` = '" . $row['BundleNumber'] . "';";
$result2 = mysql_query($sql);
while($row = mysql_fetch_array($result2)) {
if($row[0] != "") {
$final[] = $row;
} else {
$final[] = array("Can't find bundle number", "N/A");
}
}
}
return $final;
}
public function GetRoomTotalForDay($room, $date = null) {
if(!isset($date)) {
$date = date("Y-m-d");
}
// This function is going to return the number of shoes processed that day
// First of all work out which scanner number is required for the room
$scanner = $this->GetScannerNumber($room);
// Next generate the SQL
$sql = "SELECT `scanners.KordNo`, `scanners.BundleNumber`
FROM `scanners,TWOrder,Stock`
INNER JOIN TWORDER ON `scanners.KordNo` = `TWOrder.KOrdNo`
AND `scanners.Date` = '" . $date . "'
INNER JOIN Stock ON `TWOrder.Product` = `Stock.ProductCode`
AND `Stock.ProductGroup` NOT BETWEEN 400 AND 650
AND `scanners.Scanner` IN (
ORDER BY `scanners.KordNo' ASC";
foreach($scanner as $x) {
$sql .= $x . ",";
}
$sql .= "0);";
// And query the database
$result = mysql_query($sql);
while($row = mysql_fetch_array($result)) {
$return[] = $row;
}
// It is more complicated for Kettering, Closing & Rushden, we need to filter the list
if(in_array($room, array(3,4,5))) {
foreach($return as $x) {
$sql = "SELECT `scanners.Scanner`
FROM `scanners`
WHERE `scanners.KordNo` = " . $x['scanners.KordNo'] . "
AND `scanners.BundleNumber` = " . $x['scanners.BundleNumber'] . "
ORDER BY `scanners.Date` DESC
LIMIT 1,1;";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
// If scanner 7, it's been through bottom stock so need to find previous
if($row[0] == 7) {
$sql = "SELECT `scanners.Scanner`
FROM `scanners`
WHERE `scanners.KordNo` = " . $x['scanners.KordNo'] . "
AND `scanners.BundleNumber` = " . $x['scanners.BundleNumber'] . "
ORDER BY `Date` DESC
LIMIT 2,1;";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
}
if($row[0] == 10 && $room == 3) {
$finalReturn[] = $x;
} elseif($row[0] == 11 && $room == 4) {
$finalReturn[] = $x;
} elseif($row[0] == 15 && $room == 5) {
$finalReturn[] = $x;
}
}
$return = $finalReturn;
}
// Now we have a list of tickets, we need to query how many pairs are in each ticket
$total = 0;
foreach($return as $x) {
$sql = "SELECT `QtyIssued`
FROM `ArchiveBundle`
WHERE `KordNo` = '" . $x['scanners.KordNo'] . "'
AND `BundleNumber` = '" . $x['scanners.BundleNumber'] . "';";
$result = mysql_query($sql);
$row = mysql_fetch_row($result);
$total += $row[0];
}
return $total;
}
// We need a function to select the previous Monday from a given date
public function GetPreviousMonday($timestamp) {
if(date("N", $timestamp) == 1) {
return $timestamp;
} elseif(in_array(date("N", $timestamp), array(2, 3, 4, 5))) {
return $timestamp - (date("N", $timestamp)-1)*DAY;
} elseif(in_array(date("N", $timestamp), array(6, 7))) {
return $timestamp + (date("N", $timestamp)*(-1)+8)*DAY;
} else {
return false;
}
}
public function GetRoomName($room) {
// Return the room name from the room number
switch($room) {
case 1:
return "Skin Room";
case 2:
return "Clicking Room";
case 3:
return "Kettering";
case 4:
return "Closing Room";
case 5:
return "Rushden";
case 6:
return "Assembly Room";
case 7:
return "Lasting Room";
case 8:
return "Making Room";
case 9:
return "Finishing Room";
case 10:
return "Shoe Room";
}
}
public function GetDueDateForWorksOrder($worksOrderNumber) {
$sql = "SELECT `DueDate`
FROM `TWOrder`
WHERE `WorksOrderNumber` = '" . $worksOrderNumber . "';";
mysql_select_db(DB_DATABASE_NAME, $this->conn);
$result = mysql_query($sql, $this->conn);
$row = mysql_fetch_row($result);
return $row[0];
}
private function GetScannerNumber($room) {
// Get the room number from the scanner number
switch($room) {
case 1:
$scanner = array(3);
break;
case 2:
$scanner = array(10,11,15);
break;
case 3:
$scanner = array(5);
break;
case 4:
$scanner = array(5);
break;
case 5:
$scanner = array(5);
break;
case 6:
$scanner = array(6);
break;
case 7:
$scanner = array(9);
break;
case 8:
$scanner = array(8);
break;
case 9:
$scanner = array(12);
break;
case 10:
$scanner = array(14);
break;
default:
$scanner = array(0);
break;
}
return $scanner;
}
}
这里的数组项应该是$x['scanners.BundleNumber']。您是否尝试返回生成的SQL字符串,然后手动测试该字符串?我在第一个数组上执行了var_转储,它返回一个空数组。在sql server上运行的sql与这两个类都匹配。foreach$scanner作为$x{$sql.=$x.,;}将生成无效的sql片段,因为IN值的提升将以逗号结束。将0添加到$scanner数组中,然后使用内爆“,”,$scanner;相反另外,$scanner数组的内容被正确转义了,对吗?哦,还有一点关于编码风格的建议,您的函数太长了,乍一看似乎运行4或5个SQL查询。这么大的函数往往不是个好主意,因为它们更难维护或重用。作为一个一般的经验法则,我喜欢应用,如果一个函数/方法在我的IDE中不仅仅是一屏文本,那么它向我表明应该分解它。此外,DB查询函数应该运行1个查询,并且只能运行1个查询。每个查询包含一个操作,代码中的每个函数只能执行一个任务。我不明白这一点。你能举个例子吗?使用一个好的编辑器有助于防止这种错误。从ActiveState尝试Komodo IDE-有一个免费版本可用。
if(in_array($room, array(3,4,5))) {
foreach($return as $x) {
$sql = "SELECT `scanners.Scanner`
FROM `scanners`
WHERE `scanners.KordNo` = " . $x['scanners.KordNo'] . "
AND `scanners.BundleNumber` = " . $x['scanner.BundleNumber'] .