Php Mysql-Codeigniter活动记录帮助

我有一个从数据库中提取数据的代码

$this->db->select('job_id, jobs.employer_id, COUNT(company_job_id) AS views, COUNT(like_job_id) AS likes, logo, company_name')
        ->from('jobs')
        ->join('company_likes', 'company_likes.like_job_id = jobs.employer_id', 'left')
        ->join('company_views', 'company_views.company_job_id = jobs.employer_id', 'left')
        ->join('employers', 'employers.employer_id = jobs.employer_id', 'left')
        ->group_by('company_views.company_job_id');

        $query = $this->db->get();

        return $query->result_array();

我得到了一些奇怪的结果，下面是当company_likes表中有0条记录，company views表中有6条记录时结果转储的快照

    Array
(
    [0] => Array
        (
            [job_id] => 1
            [employer_id] => 1
            [views] => 6
            [likes] => 0
            [logo] => 11d4df5e2f7db152cd9bcc3782dd03b0.jpg
            [company_name] => Test Company
        )

)

但是，如果我在company_views表中有6条记录，在company likes表中有1条记录，我会得到以下结果：

Array
(
    [0] => Array
        (
            [job_id] => 1
            [employer_id] => 1
            [views] => 6
            [likes] => 6
            [logo] => 11d4df5e2f7db152cd9bcc3782dd03b0.jpg
            [company_name] => Test Company
        )

)

就好像视图和喜欢的内容在成倍增加或是其他什么，我如何才能使我得到的是数据库中内容的真实表示呢

这是有关数据和表格的导出

--
-- Table structure for table `company_likes`
--

CREATE TABLE IF NOT EXISTS `company_likes` (
  `like_id` int(10) NOT NULL AUTO_INCREMENT,
  `like_job_id` int(11) NOT NULL,
  PRIMARY KEY (`like_id`),
  KEY `fk_company_likes_jobs1` (`like_job_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ;

--
-- Dumping data for table `company_likes`
--

INSERT INTO `company_likes` (`like_id`, `like_job_id`) VALUES
(1, 1);

-- --------------------------------------------------------

--
-- Table structure for table `company_views`
--

CREATE TABLE IF NOT EXISTS `company_views` (
  `view_id` int(10) NOT NULL AUTO_INCREMENT,
  `company_job_id` int(11) NOT NULL,
  PRIMARY KEY (`view_id`),
  KEY `fk_company_views_jobs1` (`company_job_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ;

--
-- Dumping data for table `company_views`
--

INSERT INTO `company_views` (`view_id`, `company_job_id`) VALUES
(1, 1),
(2, 1),
(3, 1),
(4, 1),
(5, 1),
(6, 1);

-- --------------------------------------------------------

--
-- Table structure for table `employers`
--

CREATE TABLE IF NOT EXISTS `employers` (
  `employer_id` int(11) NOT NULL AUTO_INCREMENT,
  `company_name` varchar(80) NOT NULL,
  `company_summary` text NOT NULL,
  `logo` varchar(60) NOT NULL,
  `alternative_ads` varchar(100) DEFAULT NULL,
  `facebook_url` varchar(100) DEFAULT NULL,
  `twitter_url` varchar(100) DEFAULT NULL,
  `user_id` int(10) NOT NULL,
  PRIMARY KEY (`employer_id`),
  KEY `fk_employers_users` (`user_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;

--
-- Dumping data for table `employers`
--

INSERT INTO `employers` (`employer_id`, `company_name`, `company_summary`, `logo`, `alternative_ads`, `facebook_url`, `twitter_url`, `user_id`) VALUES
(1, 'Test Company', 'Test company is excatly what it says it is a test company, we have created this test company so that we can see that moovjob is functioning as it should be and that everything is upload, saving, applying and generally saving as we would expect.', '11d4df5e2f7db152cd9bcc3782dd03b0.jpg', 'http://www.simonainley.info/alternative', 'http://www.facebook.com/simon.ainley', 'http://www.twitter.com/simonainley', 2),
(2, 'Test Company', 'Test company summary', '006474cf842654eb28deebec7e4dcbb9.png', 'http://www.simonainley.info/alternative', 'http://www.facebook.com/simon.ainley', 'http://www.twitter.com/simonainley', 5);

-- --------------------------------------------------------

--
-- Table structure for table `jobs`
--

CREATE TABLE IF NOT EXISTS `jobs` (
  `job_id` int(11) NOT NULL AUTO_INCREMENT,
  `job_title` varchar(80) NOT NULL,
  `sectors` varchar(255) NOT NULL,
  `salary` varchar(20) NOT NULL,
  `retrain` enum('yes','no') NOT NULL,
  `bonuses_available` enum('yes','no') NOT NULL,
  `bonus_description` text,
  `job_summary` text NOT NULL,
  `job_description` text NOT NULL,
  `employer_id` int(11) NOT NULL,
  PRIMARY KEY (`job_id`),
  KEY `fk_jobs_employers1` (`employer_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ;

--
-- Dumping data for table `jobs`
--

INSERT INTO `jobs` (`job_id`, `job_title`, `sectors`, `salary`, `retrain`, `bonuses_available`, `bonus_description`, `job_summary`, `job_description`, `employer_id`) VALUES
(1, 'Test Jobtitle', 'Sector 1', '£25,000', 'no', 'yes', 'Bonus Description', 'Job Summary', 'Job Description', 1);

--
-- Constraints for dumped tables
--

--
-- Constraints for table `company_views`
--
ALTER TABLE `company_views`
  ADD CONSTRAINT `company_views_ibfk_1` FOREIGN KEY (`company_job_id`) REFERENCES `jobs` (`employer_id`) ON DELETE NO ACTION ON UPDATE NO ACTION;

--
-- Constraints for table `employers`
--
ALTER TABLE `employers`
  ADD CONSTRAINT `fk_employers_users` FOREIGN KEY (`user_id`) REFERENCES `users` (`user_id`) ON DELETE NO ACTION ON UPDATE NO ACTION;

--
-- Constraints for table `jobs`
--
ALTER TABLE `jobs`
  ADD CONSTRAINT `fk_jobs_employers1` FOREIGN KEY (`employer_id`) REFERENCES `employers` (`employer_id`) ON DELETE NO ACTION ON UPDATE NO ACTION;

---

你想过把这个问题分解一下吗？您可以创建一个临时表来组合查询的一部分，然后用第二个查询完成初始查询的另一部分

我不相信active record类有任何东西可以创建临时表，因此您需要手动创建临时表

我还可以看到查询被分解成更小的块，并使用php为您进行一些比较和计数

---

否则，一些示例数据和表创建信息可能会很有用，因此我们也可以尝试查询。

我查看了您的数据，得出结论，您的问题是有六个视图，其中company_job_id=1。然后，每次运行此操作时，都会为“公司”视图上的join创建一个匹配结果集，并随着每次都有“公司”视图的匹配项而增加“喜欢”计数。我会做一个较小的查询，并使用php获得您想要的正确计数。我自己无法帮助您查询，我希望看到它完成，但也无法获得您正在寻找的内容。