Php %如%查询未按预期给出结果
我正在开发搜索功能,我正在根据用户输入进行查询,但没有得到预期的结果Php %如%查询未按预期给出结果,php,sql,laravel,search,laravel-5.3,Php,Sql,Laravel,Search,Laravel 5.3,我正在开发搜索功能,我正在根据用户输入进行查询,但没有得到预期的结果 //if user searches walter getting proper response http://localhost:8000/api/v1/search/walter { "data": [ { "id": 1, "first_name": "Walter", "last_name": "White", "phone_number": "96
//if user searches walter getting proper response
http://localhost:8000/api/v1/search/walter
{
"data": [
{
"id": 1,
"first_name": "Walter",
"last_name": "White",
"phone_number": "9665885542",
"registration_id": "12345b67892"
},
{
"id": 8,
"first_name": "Mitty",
"last_name": "Walter",
"phone_number": "8826835542",
"registration_id": "dffdfg54ty45y"
}
]
}
// but if user searches walt the response is
http://localhost:8000/api/v1/search/walt
{
"data": []
}
我的方法
//搜索驱动程序
公共函数getSearchResults$search\u输入{
$search_drivers = Driver::where('id', 'like', $search_input)
->orWhere('first_name', 'like', $search_input)
->orWhere('last_name', 'like', $search_input)
->orWhere('phone_number', 'like', $search_input)
->orWhere('registration_id', 'like', $search_input)
->select('id','first_name','last_name','phone_number','registration_id')
->get();
return Response::json([
'data' => $search_drivers
]);
}
在输入完整数据之前,有没有更好的方法获得结果
谢谢的正确语法为“%”。$search\u input.“%”:
我的坏,非常感谢你真的很感激,我不能在6分钟内接受答案
$search_drivers = Driver::where('id', 'like', '%'.$search_input.'%')
->orWhere('first_name', 'like', '%'.$search_input.'%')
->orWhere('last_name', 'like', '%'.$search_input.'%')
->orWhere('phone_number', 'like', '%'.$search_input.'%')
->orWhere('registration_id', 'like', '%'.$search_input.'%')
->select('id','first_name','last_name','phone_number','registration_id')
->get();