Php 为什么我的注册表表单仍然没有将数据输入MySQL表
我正在尝试将注册页面与我的登录页面链接，以允许新用户注册一个在我的应用程序上使用的帐户。我已经将表单链接到MySQL上的tbl_Users表，其中保存了用户将输入到此表单的所有信息。我已经使用查询等方法正确地设置了所有内容，表单至少可以正确地显示。但是，当我单击submit时，页面刚刚刷新，字段现在再次为空，并且数据库表中没有新数据。我哪里做错了？（额外说明：我仍在编写安全代码以防止sql注入） ConnectorCode.phpPhp 为什么我的注册表表单仍然没有将数据输入MySQL表,php,mysql,Php,Mysql,我正在尝试将注册页面与我的登录页面链接，以允许新用户注册一个在我的应用程序上使用的帐户。我已经将表单链接到MySQL上的tbl_Users表，其中保存了用户将输入到此表单的所有信息。我已经使用查询等方法正确地设置了所有内容，表单至少可以正确地显示。但是，当我单击submit时，页面刚刚刷新，字段现在再次为空，并且数据库表中没有新数据。我哪里做错了？（额外说明：我仍在编写安全代码以防止sql注入） ConnectorCode.php <?php $conn = mysqli_connec
<?php
$conn = mysqli_connect("localhost", "b4014107", "Win1", "b4014107_db2") or die (mysqli_connect_error());
?>
<?
error_reporting(E_ALL);
ini_set('display_errors', 1);
session_start();
include('ConnectorCode.php');
if(isset($_POST['submit'])) {
$FName = $_POST['First_Name'];
$LName = $_POST['Last_Name'];
$Email = $_POST['Email'];
$UName = $_POST['User_Name'];
$Password = $_POST['Password'];
$FName = mysqli_real_escape_string($conn, $FName);
$LName = mysqli_real_escape_string($conn, $LName);
$Email = mysqli_real_escape_string($conn, $Email);
$UName = mysqli_real_escape_string($conn, $UName);
$Password = mysqli_real_escape_string($conn, $Password);
$sql = "SELECT Email FROM tbl_Users WHERE Email='$Email'";
$result = mysqli_query($conn, $sql);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
if(mysqli_num_rows($result) == 1)
{
echo "Sorry, the email you are trying to enter already exists";
}
else
{
$query = mysqli_query($conn, "INSERT INTO tbl_Users(First_Name, Last_Name, Email, User_Name, Password) VALUES ('$FName', '$LName', '$Email', '$UName', '$Password')");
if($query)
{
echo "Thank you for registering";
}
header('Location: Index.php');
}
}
?>
<!DOCTYPE HTML>
<head>
<title>Register</title>
</head>
<body>
<h1> Register Page </h1>
<p> Please fill in the form to register <p>
<form method="post" action="">
<fieldset>
First Name: <br />
<input name="First_Name" type="text" class="input" size="25" required /> <br /> <br />
Last Name: <br />
<input name="Last_Name" type="text" class="input" size="25" required /> <br /> <br />
Email: <br />
<input name="Email" type="email" class="input" size="25" required /> <br /> <br />
Username: <br />
<input name="User_Name" type="text" class="input" size"25" required /> <br /> <br />
Password: <br />
<input name="Password" type="password" class="input" size="25" required /> <br /> <br/>
<input type="submit" name="submit" value="Register!" />
</fieldset>
</form>
</body>
</html>
<?php
$conn = mysqli_connect("localhost", "b4014107", "Win1", "b4014107_db2") or die (mysqli_connect_error());
?>
<?
error_reporting(E_ALL);
ini_set('display_errors', 1);
session_start();
include('ConnectorCode.php');
if(isset($_POST['submit'])) {
$FName = $_POST['First_Name'];
$LName = $_POST['Last_Name'];
$Email = $_POST['Email'];
$UName = $_POST['User_Name'];
$Password = $_POST['Password'];
$FName = mysqli_real_escape_string($conn, $FName);
$LName = mysqli_real_escape_string($conn, $LName);
$Email = mysqli_real_escape_string($conn, $Email);
$UName = mysqli_real_escape_string($conn, $UName);
$Password = mysqli_real_escape_string($conn, $Password);
$sql = "SELECT Email FROM tbl_Users WHERE Email='$Email'";
$result = mysqli_query($conn, $sql);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
if(mysqli_num_rows($result) == 1)
{
echo "Sorry, the email you are trying to enter already exists";
}
else
{
$query = mysqli_query($conn, "INSERT INTO tbl_Users(First_Name, Last_Name, Email, User_Name, Password) VALUES ('$FName', '$LName', '$Email', '$UName', '$Password')");
if($query)
{
echo "Thank you for registering";
}
header('Location: Index.php');
}
}
?>
<!DOCTYPE HTML>
<head>
<title>Register</title>
</head>
<body>
<h1> Register Page </h1>
<p> Please fill in the form to register <p>
<form method="post" action="">
<fieldset>
First Name: <br />
<input name="First_Name" type="text" class="input" size="25" required /> <br /> <br />
Last Name: <br />
<input name="Last_Name" type="text" class="input" size="25" required /> <br /> <br />
Email: <br />
<input name="Email" type="email" class="input" size="25" required /> <br /> <br />
Username: <br />
<input name="User_Name" type="text" class="input" size"25" required /> <br /> <br />
Password: <br />
<input name="Password" type="password" class="input" size="25" required /> <br /> <br/>
<input type="submit" name="submit" value="Register!" />
</fieldset>
</form>
</body>
</html>
您不符合条件isset（$\u POST['VALUES']），因为您没有name=“VALUES”字段
改变
if(isset($_POST['VALUES'])) {
到
你错过了很多
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
session_start();
require_once 'ConnectorCode.php';
if(isset($_POST['submit']))
{
$FName = mysqli_real_escape_string($conn, $_POST['First_Name']);
$LName = mysqli_real_escape_string($conn, $_POST['Last_Name']);
$Email = mysqli_real_escape_string($conn, $_POST['Email']);
$UName = mysqli_real_escape_string($conn, $_POST['User_Name']);
$Password = mysqli_real_escape_string($conn, $_POST['Password']); // why did you need to repeat this all twice?
$sql = "SELECT * FROM tbl_Users WHERE Email='$Email'"; // ? didn't understand why you was asking for the Email using the Email...
$result = $conn->query($sql);
if(count($result) == 0)
{
$insert_sql = "INSERT INTO tbl_Users (First_Name,Last_Name,Email,User_Name,Password) VALUES ('$FName','$LName','$Email','$UName','$Password')";
if($conn->query($insert_sql)) // You forgot to query this
{
echo "Thank you for registering";
header('Location: index.php'); // lowercase i
exit; // you forgot this
}
}
else
{
echo "Sorry, that email already exists!";
}
$conn->close(); // you forgot this
}
?>
session_start（）的第一个需要在顶部。第二个表单代码要求？您可以添加表单的代码，并请发布它显示给您的错误（如果有）表单代码在那里，它在代码表的底部。submit
！=<代码>提交
。所以这永远不会发生。哈哈哈$POST
就是问题所在。它应该是$\u POST
我已经更改了它，但是我的数据库表中仍然没有新行。没有！这就是令人困惑的地方，屏幕顶部没有显示错误消息，所发生的只是字段刷新，没有新数据输入到表中。非常感谢！但是现在，每次我加载php文件时，都会在页面顶部弹出query（$query））{echo“感谢您注册”；header（'Location:index.php'）；exit；}}否则{echo“对不起，该电子邮件已经存在！”；}$conn->close（）；}？>立即尝试，已编辑。不管怎样，我现在正在完成工作，这样应该可以解决你的问题。祝你好运。现在它显示了这个查询（$sql）；if（count（$result）==0）{$insert_sql=“insert INTO tbl_Users（First_Name，Last_Name，Email，User_Name，Password）”值（'$FName'，'$LName'，'$Email'，'$UName'，'$Password'）；if（$conn->query（$insert_sql））{echo“感谢您的注册”；header（'Location:index.php'）；退出；}否则{echo“对不起，那封电子邮件已经存在”；}$conn关闭（）; } ?> 这是->语法，我想，它似乎不喜欢它。你正在运行什么PHP版本？可能$result返回的是一个布尔值而不是查询数据，只需使用折旧后的mysqli\u查询
而不是->
，就可以了。祝你好运