Php 基于值​；构建一个图表；在两个时间段之间从数据库中

我正在尝试根据Ms SQL数据库中的值构建一个图表。这里是我的想法，但只展示了一点：

<?php

//----------------------Connect with Server--------------------------
$serverName = "DESKTOP-MLENLVF"; 
$connectionInfo = array( "Database"=>"DataBaseExample", "UID"=>"g.abibekov", "PWD"=>"dprb-725");
$conn = sqlsrv_connect( $serverName, $connectionInfo);
//----------------------End Connecting with Server--------------------------


if(isset($_POST["FirstDateButton"]))
{
    $firstdatetime=htmlspecialchars($_POST['FirstDate']);
    $seconddatetime=htmlspecialchars($_POST['SecondDate']);
    $query=sqlsrv_query($conn, "SELECT * FROM ValueTime WHERE Date between cast('$firstdatetime' as Date) 
    and cast('$seconddatetime' as Date)"); 
    while($row=sqlsrv_fetch_array($query))
    {        
       $dataPoints = array(array("y" => $row['Value'], "label" => $row['Date']));
    }
}
?>

---

只使用
$dataPoints=array（array（“y”=>$row['Value']，“label”=>$row['Date']）
您正在覆盖
$dataPoint
中的所有数据，并仅存储
while
循环中的最后一个值

为了解决这个问题，您可以这样做：

while($row=sqlsrv_fetch_array($query))
{
  $dataPoints[] = array(array("y" => $row['Value'], "label" => $row['Date']));
}

while($row=sqlsrv_fetch_array($query))
{        
   $tmp = array(array("y" => $row['Value'], "label" => $row['Date']));
   array_push($dataPoints, $tmp);
}

或者像这样：

while($row=sqlsrv_fetch_array($query))
{
  $dataPoints[] = array(array("y" => $row['Value'], "label" => $row['Date']));
}

while($row=sqlsrv_fetch_array($query))
{        
   $tmp = array(array("y" => $row['Value'], "label" => $row['Date']));
   array_push($dataPoints, $tmp);
}

sqlsrv\u num\u行（$query）
请检查，