PHP使用特定模式从末尾拆分字符串

我有这些绳子，它们是医院和城市的结合体。我想分开，只知道医院的名字

ABC Hospital (rawalpindi)
ABC Hospital (New) (Rawalpindi)
XYZ Hospital (old) (Lahore)

我想将字符串从末尾拆分，这样输出应该是正确的

ABC Hospital
ABC Hospital (New)
XYZ Hospital (old)

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利用子字符串生成最后位置为

“

的较小字符串

使用示例代码：

$s1 = "ABC Hospital (rawalpindi)";
$s2 = "ABC Hospital (New) (Rawalpindi)";
$s3 = "XYZ Hospital (old) (Lahore)";

echo substr($s1, 0, strripos($s1," "));
echo substr($s2, 0, strripos($s2," "));
echo substr($s3, 0, strripos($s3," "));

这将产生以下输出：

ABC Hospital
ABC Hospital (New)
XYZ Hospital (old)

这是一个简单的正则表达式：

foreach(array('ABC Hospital (rawalpindi)', 'ABC Hospital (New) (Rawalpindi)', 'XYZ Hospital (old) (Lahore))') as $name){
  echo preg_replace('/(.*) \(.*/', '\1', $name) . "\n";
}

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你有没有试过自己解决这个问题？逻辑是什么？请添加更多信息<代码>（新）和

（旧）

被接受，而不是其他的？@MTaqi这些答案对你有帮助吗？

foreach(array('ABC Hospital (rawalpindi)', 'ABC Hospital (New) (Rawalpindi)', 'XYZ Hospital (old) (Lahore))') as $name){
  echo preg_replace('/(.*) \(.*/', '\1', $name) . "\n";
}