PHP JSON_解码数组

我使用以下代码来解码json数组

$json_contacts ='[{"addr_name":"1","addr_phone":"010-1111-1111"},{"addr_name":"2","addr_phone":"010-1111-1112"},{"addr_name":"3","addr_phone":"010-1111-1113"},{"addr_name":"4","addr_phone":"010-1111-1114"}]';

$contact = json_decode($json_contacts, true);
echo $json_contacts;
echo "\n";
echo $contact;
echo "\nTHE END";

我得到以下结果

[{"addr_name":"1","addr_phone":"010-1111-1111"},{"addr_name":"2","addr_phone":"010-1111-1112"},{"addr_name":"3","addr_phone":"010-1111-1113"},{"addr_name":"4","addr_phone":"010-1111-1114"}]

THE END

为什么我的JSON_DECODE没有正确解码数组？

尝试以下方法：

<?php
$json_contacts ='[{"addr_name":"1","addr_phone":"010-1111-1111"},{"addr_name":"2","addr_phone":"010-1111-1112"},{"addr_name":"3","addr_phone":"010-1111-1113"},{"addr_name":"4","addr_phone":"010-1111-1114"}]';

$contact = json_decode($json_contacts, true);
echo $json_contacts;
echo "\n";
echo '<pre>';
print_r( $contact);

echo '</pre>';
echo "\nTHE END";

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在php上打开错误报告-已尝试但没有错误…我已检查了您的代码，并在“echo$contact；”行中显示警告，改为“print_r（$contact）；”并打印所有数组值。我不是那么新手。。。当然，脚本是用in编写的。否则它就不会显示我上面提到的结果。@HamDongKyun我知道你不是新手。请把这些都抄下来。并打印（$contact）；不回显$contact。