Php 替换“；加上\"；，仅当用“报价”括起时；

我正在从数据库中读取一个json_encode不起作用的字符串。（使用PHP）

我需要将所有出现的

“

替换为

\”

，但前提是该出现已包含在

“

中

示例字符串：

{"val1": "This is "some value" that is inside of the "string" and such", "val2": "And here is yet another "value" that is messed up by quotation marks", "val3": "etc. etc."}

应改为：

{"val1": "This is \"some value\" that is inside of the \"string\" and such", "val2": "And here is yet another \"value\" that is messed up by quotation marks", "val3": "etc. etc."}

---

尝试以下说明：

string '{"val1": "This is "some value" that is inside of the "string" and such", "val2": "And here is yet another "value" that is messed up by quotation marks", "val3": "etc. etc."}' (length=173)

string '{\"val1\": \"This is \"some value\" that is inside of the \"string\" and such\", \"val2\": \"And here is yet another \"value\" that is messed up by quotation marks\", \"val3\": \"etc. etc.\"}' (length=191)

string '{"val1": "This is \"some value\" that is inside of the \"string\" and such", "val2": "And here is yet another \"value\" that is messed up by quotation marks", "val3": "etc. etc."}' (length=179)

首先，将

“

替换为

\”

并按照以下方式再次替换为正则表达式：

$a='{"val1": "This is "some value" that is inside of the "string" and such", "val2": "And here is yet another "value" that is messed up by quotation marks", "val3": "etc. etc."}';
var_dump($a);
$a=str_replace('"','\"',$a);
var_dump($a);
$re = "~(\\\\\")([^\":]+)(\\\\\"):\\s*(\\\\\")([^,]+)(\\\\\")([,}])~m"; 
$str =$a;
$subst = "\"$2\": \"$5\"$7"; 
$a=preg_replace($re, $subst, $str);
var_dump($a);

输出：

string '{"val1": "This is "some value" that is inside of the "string" and such", "val2": "And here is yet another "value" that is messed up by quotation marks", "val3": "etc. etc."}' (length=173)

string '{\"val1\": \"This is \"some value\" that is inside of the \"string\" and such\", \"val2\": \"And here is yet another \"value\" that is messed up by quotation marks\", \"val3\": \"etc. etc.\"}' (length=191)

string '{"val1": "This is \"some value\" that is inside of the \"string\" and such", "val2": "And here is yet another \"value\" that is messed up by quotation marks", "val3": "etc. etc."}' (length=179)

---

哈哈，你怎么知道你什么时候碰到了一个结束语

“

”？json_到底是如何编码“不工作”的？json_encode不可能产生无效的json。它要么成功，要么返回布尔值false。它不会返回无效的json字符串。请修复您的数据库插入代码或放弃手动json构造。你无法可靠地修复损坏。（顺便说一句，你试过什么吗？）我同意马里奥的观点，你需要解决问题的根本原因。出于好奇，如果用单引号封装字符串会发生什么？json_encode会转义“.”的所有出现。当使用单引号时，它会起作用-所以现在我将避免使用双引号，直到我可以按照建议修复插入。