Php 如何将数组转换为多维数组
我有一个数组要转换为多维数组 这是数组Php 如何将数组转换为多维数组,php,mysql,arrays,multidimensional-array,Php,Mysql,Arrays,Multidimensional Array,我有一个数组要转换为多维数组 这是数组 Array ( [0] => Array ( [packageid] => FGF1460676803 [uniqueid] => uid1460676987 [hotelname] => Jet Park Airport [Country] => New Zealand ) [1]
Array
(
[0] => Array
(
[packageid] => FGF1460676803
[uniqueid] => uid1460676987
[hotelname] => Jet Park Airport
[Country] => New Zealand
)
[1] => Array
(
[packageid] => FGF1460678556
[uniqueid] => uid1460678681
[hotelname] => Mercure Windsor
[Country] => New Zealand
)
[2] => Array
(
[packageid] => FGF1460678556
[uniqueid] => uid1460678787
[hotelname] => Jet Park Airport
[Country] => New Zealand
)
)
SELECT
c.packageid,
`uniqueid`,
`hotelname`,
`Country`
FROM
custinfo c,
hotelcarttemp h
WHERE
c.packageid = h.packageid
我已经尝试过这个代码,但它没有显示我想要的。
这个数组是从mysql的两个表中获取的,第一个是carry packageid,第二个是uniqueid,hotelname,country,所以我加入了它,但是我想加入下面的数组,但是我被困在如何使用mysql或者在获取数组之后
这是mysql查询
Array
(
[0] => Array
(
[packageid] => FGF1460676803
[uniqueid] => uid1460676987
[hotelname] => Jet Park Airport
[Country] => New Zealand
)
[1] => Array
(
[packageid] => FGF1460678556
[uniqueid] => uid1460678681
[hotelname] => Mercure Windsor
[Country] => New Zealand
)
[2] => Array
(
[packageid] => FGF1460678556
[uniqueid] => uid1460678787
[hotelname] => Jet Park Airport
[Country] => New Zealand
)
)
SELECT
c.packageid,
`uniqueid`,
`hotelname`,
`Country`
FROM
custinfo c,
hotelcarttemp h
WHERE
c.packageid = h.packageid
PHP代码
foreach ($json_decode_array1 as $row)
{
$newArray[$row['packageid']][] = $row;
}
echo '<pre>'; print_r($newArray); echo '</pre>';
试试这个:
$newArr = array();
foreach($json_decode_array1 as $row) {
$temp = array();
$temp['packageid'] = $row['packageid'];
$temp['hoteldata'] = array(
'uniqueid' => $row['uniqueid'],
'hotelname' => $row['hotelname'],
'Country' => $row['Country'],
);
$newArr[] = $temp;
}
echo '<pre>';print_r($newArr);
试试这个
$result = [];
array_walk($arr, function($v) use(&$result) { // $arr is your initial array
$packageid = array_shift($v);
if (!isset($result[$packageid])) {
$result[$packageid] = ["packageid" => $packageid, "hoteldata" => [$v]];
} else {
$result[$packageid]["hoteldata"][] = $v;
}
});
print_r(array_values($result));
$newArr=array();
foreach($json_decode_array1作为$row){
$temp=array();
$temp['packageid']=$row['packageid'];
$temp['hoteldata']=数组(
'uniqueid'=>$row['uniqueid'],
'hotelname'=>$row['hotelname'],
“国家”=>$row[“国家”],
);
$newArr[]=$temp;
}
回声';印刷费($newArr);
使用array\u walk
、array\u shift
和array\u value
功能的解决方案:
输出:
$newArray[$pid]['hoteldata']=$row
这将覆盖数组(),而不是按$row
@u\u mulder非常感谢您的回答,但它会显示这样的输出@VijayKumar修复了我的答案:在$newArray[$pid]=array()
@u\u mulder您真的需要在第8行设置'hoteldata'=>array()。在你最终创建密钥时,这是必要的吗?@PetkoKostov这不是必要的,但我想知道我这里有什么。
Array
(
[0] => Array
(
[packageid] => FGF1460676803
[hoteldata] => Array
(
[0] => Array
(
[uniqueid] => uid1460676987
[hotelname] => Jet Park Airport
[Country] => New Zealand
)
)
)
[1] => Array
(
[packageid] => FGF1460678556
[hoteldata] => Array
(
[0] => Array
(
[uniqueid] => uid1460678681
[hotelname] => Mercure Windsor
[Country] => New Zealand
)
[1] => Array
(
[uniqueid] => uid1460678787
[hotelname] => Jet Park Airport
[Country] => New Zealand
)
)
)
)