Php 用pdo连接两个表
我想联接数据库中的两个表。它以“经典”的方式工作得很好,但是我的脚本中有一大堆select查询,所以我想缩短它 以下是联合sql:Php 用pdo连接两个表,php,mysql,join,Php,Mysql,Join,我想联接数据库中的两个表。它以“经典”的方式工作得很好,但是我的脚本中有一大堆select查询,所以我想缩短它 以下是联合sql: SELECT matches.id, matches.start_time, matches.category_id, matches.highl, first_team.tid, first_team.t_name, second_team.tid, second_team.t_name AS ft_name FROM matches
SELECT
matches.id, matches.start_time, matches.category_id,
matches.highl, first_team.tid, first_team.t_name,
second_team.tid, second_team.t_name AS ft_name
FROM matches
INNER JOIN teams AS first_team ON matches.first_team_id = first_team.tid
INNER JOIN teams AS second_team ON matches.second_team_id = second_team.tid
ORDER BY matches.id DESC
LIMIT 10
我想要实现的是这样的,但我不知道如何添加我上面复制的所有值
public function getMatches($table,$conditions = array()){
$sql = 'SELECT ';
$sql .= array_key_exists("select",$conditions)?$conditions['select']:'';
$sql .= ' FROM '.$table;
if(array_key_exists("where",$conditions)){
$sql .= ' WHERE ';
$i = 0;
foreach($conditions['where'] as $key => $value){
$pre = ($i > 0)?' AND ':'';
$sql .= $pre.$key." = '".$value."'";
$i++;
}
}
if(array_key_exists("inner_join",$conditions)){
$sql .= ' INNER JOIN '.$conditions['inner_join'];
}
if(array_key_exists("on",$conditions)){
$sql .= ' ON '.$conditions['on'];
}
if(array_key_exists("as",$conditions)){
$sql .= ' AS '.$conditions['as'];
}
if(array_key_exists("order_by",$conditions)){
$sql .= ' ORDER BY '.$conditions['order_by'];
}
if(array_key_exists("start",$conditions) && array_key_exists("limit",$conditions)){
$sql .= ' LIMIT '.$conditions['start'].','.$conditions['limit'];
}elseif(!array_key_exists("start",$conditions) && array_key_exists("limit",$conditions)){
$sql .= ' LIMIT '.$conditions['limit'];
}
$query = $this->db->prepare($sql);
$query->execute();
if(array_key_exists("return_type",$conditions) && $conditions['return_type'] != 'all'){
switch($conditions['return_type']){
case 'count':
$data = $query->rowCount();
break;
case 'single':
$data = $query->fetch(PDO::FETCH_ASSOC);
break;
default:
$data = '';
}
}else{
if($query->rowCount() > 0){
$data = $query->fetchAll();
}
}
return !empty($data)?$data:false;
}
}
以下是输出:
<div class="panel-heading">Matches</div>
<table class="table">
<tr>
<th>#</th>
<th>First Team</th>
<th>Second Team</th>
<th>Start Time</th>
</tr>
<?php
include 'inc/functions.php';
$db = new DB();
$matches = $db->getMatches('matches', array('inner_join'=>'teams'), array('as'=>'first_team'), array('on'=>'matches.first_team_id = first_team.tid'), array('inner_join'=>'teams'), array('as'=>'second_team'), array('on'=>'matches.second_team_id = second_team.tid'), array('order_by'=>'matches.id'));
if(!empty($matches)){ $count = 0; foreach($matches as $result){ $count++;?>
<tr>
<td><?php echo $count; ?></td>
<td><?php echo $result['ft_name']; ?></td>
<td><?php echo $result['t_name']; ?></td>
<td><?php echo $result['start_time']; ?></td>
</tr>
<?php } }else{ ?>
<tr><td colspan="4">No entry found!</td>
<?php } ?>
</table>
</div>
老实说,就我个人而言,我永远都不会明白,PHP数组的墙是如何形成的
array('inner_join'=>'teams'), array('as'=>'first_team'),
array('on'=>'matches.first_team_id = first_team.tid'),
array('inner_join'=>'teams'),
array('as'=>'second_team'),
array('on'=>'matches.second_team_id = second_team.tid'),
array('order_by'=>'matches.id'));
甚至可以远比优雅紧凑的SQL短
SELECT
matches.id, matches.start_time, matches.category_id,
matches.highl, first_team.tid, first_team.t_name,
second_team.tid, second_team.t_name AS ft_name
FROM matches
INNER JOIN teams AS first_team ON matches.first_team_id = first_team.tid
INNER JOIN teams AS second_team ON matches.second_team_id = second_team.tid
ORDER BY matches.id DESC
LIMIT 10
更不用说它的意义和可读性了
你是不是想省去键入一些SQL关键字,比如SELECT或FROM?认真地把一个有意义且易于理解的SQL弄得一团糟真的值得吗?您希望我们在这里做什么?您的问题是什么?选择后的值和选择前的值。如何添加它们?matches.id,matches.start_time,matches.category_id,matches.highl,first_team.tid,first_team.t_name,second_team.tid,second_team.t_name作为ft_name真正感兴趣-您是否真的发现以这种方式构建查询比手动编译查询更容易?顺便说一下,PDO不会加入您的表。它只是将您编写的SQL查询发送到mysql。删除tagok,假设我将函数命名为“getData”,并使用非联接表。我只是写了一个例子:$users=$db->getData'accounts',array'order_by'=>'id';//php:$sql='SELECT'$sql.=array_key_existsselect,$conditions?$conditions['select']:'*'$sql.='来自'.$表;因此,您再次尝试节省一些SQL关键字。打字真的那么难吗?特别是考虑到您的用户正在用它们来换取PHP代码。为什么你想削弱你的SQL,让它成为一些有限的和胡言乱语的PHP方言呢?我明白了,你可能是对的。也许在最后,“正常”的方式更有用,但现在我想这样做。那么,你能帮我一下吗?你最好考虑一下如何使你的查询对SQL注入安全。这真的值得你和我花时间