Php MySQLi-将表值作为字符串而不是对象获取

我试图使用php从我的用户MySQL表中检索名称和用户电子邮件值，如下所示：

我正在使用以下代码试图获取当前登录用户的名称和用户电子邮件：

<?php
session_start();
#connect to MySQL database
require_once("settings.php");
$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);

#get username of current session
$username = $_SESSION['username'];

#get userEmail of logged-in user from database
$sql = "SELECT userEmail from Users WHERE username LIKE '{$username}' LIMIT 1";
$result = $mysqli->query($sql);
$replyTo = mysqli_fetch_field($result);

#get name of logged-in user from database
$sql2 = "SELECT name from Users WHERE username LIKE '{$username}' LIMIT 1";
$result2 = $mysqli->query($sql2);
$name = mysqli_fetch_field($result2);
?>

…并获取以下错误：

警告：trim（）希望参数1是字符串，对象在/var/www/phpmailer/class.phpmailer.php行489中给出（该对象是$replyTo）

可捕获的致命错误：stdClass类的对象无法在/var/www/phpmailer/class.phpmailer.php行490中转换为字符串（此对象为$name）

使用Chrome Logger进行调试，我发现这些是$userEmail和$name的值：

<?php
session_start();
#connect to MySQL database
require_once("settings.php");
$mysqli = new mysqli(DB_HOST, DB_USER, DB_PASS, DB_NAME);

#get username of current session
$username = $_SESSION['username'];

#get userEmail of logged-in user from database
$sql = "SELECT userEmail from Users WHERE username LIKE '{$username}' LIMIT 1";
$result = $mysqli->query($sql);
$replyTo = mysqli_fetch_field($result);

#get name of logged-in user from database
$sql2 = "SELECT name from Users WHERE username LIKE '{$username}' LIMIT 1";
$result2 = $mysqli->query($sql2);
$name = mysqli_fetch_field($result2);
?>

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我认为您可以通过一次查询获得电子邮件和姓名-出于安全原因，使用准备好的语句（SQLIA）

---

您使用了错误的函数。返回列元数据-不是值。哈，是的，我认为是。我通常默认W3Schools，尽管我在这里看到有人强烈反对W3Schools。出于某种原因，Google和W3schools在这个特定项目上让我不及格（更像是我自己不及格）是的，这是

bind_param

并保留

username=？

。。如果您使用

WHERE username='{$username}'

，则不需要使用bind_param，这是一种不好的方法，因为它现在为它们分配了正确的值。非常感谢！

#get userEmail of logged-in user from database
$sql = "SELECT userEmail,name from Users WHERE username = ? LIMIT 1";
// this is prepared statement and prevent form sql injection attack
$statement = $mysqli->prepare($sql);
$statement->bind_param('s',$username);
$statement->execute();
$result = $statement->get_result();
// fetch first record in associative array
$userDetail = $result->fetch_assoc();
if($userDetail)
{
   $replyTo = $userDetail['userEmail'];
   $name = $uerDetail['name'];
   $mail->setFrom($replyTo, $name);
}
else
{
   echo 'user not found';
}