无法将php代码添加到变量？
每次用户注册我的网站时，我都会尝试创建一个PHP文件。我使用以下代码在我的无法将php代码添加到变量？,php,file,Php,File,每次用户注册我的网站时，我都会尝试创建一个PHP文件。我使用以下代码在我的register.php中创建文件： 问题是，我的create file函数可以工作，但是变量$data不会给出任何结果。当我将$data作为一个变量在不同的PHP文件中运行时，它仍然不起作用 设置变量时我做错了什么 // STARTING to create a file $my_file = "$username.php"; $handle = fopen("give/$my_file", 'w
register.php$data$data // STARTING to create a file
$my_file = "$username.php";
$handle = fopen("give/$my_file", 'w') or die('Cannot open file: '.$my_file);
//----------- BEGINNING OF THE PHP DATA TO WRITE TO NEW FILE ----------
$data = "<?
require('../config.inc.php');
$damned_user = $username;
if ( $_COOKIE['damn_given'] != TRUE ) {
$sql = mysql_query(\"SELECT * FROM users WHERE username='$damned_user' LIMIT 1\");
if(mysql_num_rows($sql) == 1){
$row = mysql_fetch_array($sql);
// $row['field'];
$damned_user_id = $row['id'];
if($_SESSION['id'] == $damned_user_id) {
} else {
$taken = $row['taken_damns'];
$taken_damns = $taken + 1;
$taking_sql = \"UPDATE users SET taken_damns='$taken_damns' WHERE username='$damned_user' \";
if (mysql_query($taking_sql)) {
setcookie(\"damn_given\", TRUE, time()+3600*24);
$date = date(\"Y-m-d H:i:s\");
$ip = $_SERVER['REMOTE_ADDR'];
$damns_table = \"INSERT INTO damns (id, from_ip, user_damned, when_damned) VALUES ('','$ip','$damned_user','$date') \";
if ( mysql_query($damns_table)) {
} else {
echo \"Couldn't save damn to damns table in database!\";
}
if ( $_SESSION['logged'] == TRUE ) {
$session_id = $_SESSION['id'];
$giving_sql = \"UPDATE users SET given_damns='$taken_damns' WHERE id='$session_id'\";
if ( mysql_query($giving_sql ) ) {
} else {
echo ('Error giving damn!');
}
}
}
else
{
die (\"Error taking damn!\");
}
}
} else {
die(\"Error first sql!\");
}
}
?>
<html>
<head>
<meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" />
<link rel=\"stylesheet\" href=\"/_common.css\" />
<link rel=\"stylesheet\" href=\"/_col_white.css\" />
<link rel=\"shortcut icon\" href=\"/favicon.ico\" /> <title>DamnIt.tk - Damned!</title>
</head>
<body>
<div id=\"main\">
<div class=\"center\"><a href=\"/\"><img src=\"/_bnr_white.png\" style=\"width: 500px; height: 100px;\" alt=\"DamnIt Banner\" /></a></div>
<table class=\"tmid\" style=\"width: 100%;\"><tr>
<td class=\"center\" style=\"width: 25%;\"><a href=\"/profile\">Profile</a></td>
<td class=\"center\" style=\"width: 25%;\"><a href=\"/options\">Options</a></td>
<td class=\"center\" style=\"width: 25%;\"><a href=\"/stats\">Stats</a></td>
<td class=\"center\" style=\"width: 25%;\"><a href=\"/logout\">Log out</a></td>
</tr></table> <h1>Give a Damn</h1>
<?
if ( isset($_COOKIE['damn_given'])) {
?>
<h2>You have already given a Damn to <? echo $damned_user ?> today!</h2><h3>Couldn't damn - try again tomorrow.</h3>
<?
}
elseif ( $_SESSION['id'] == $damned_user_id ) {
?>
<h2>You cannot damn yourself!</h2>
<?
} else{ ?> <h2>Damn given!</h2><h3>You have given a Damn to <? echo $damned_user ?>.</h3> <? } ?>
</div></body>
</html>";
//------- END OF PHP WHICH MUST BE WRITTEN TO NEW FILE ---------
fwrite($handle, $data);
fclose($handle);
// finished with the file
//开始创建文件
$my_file=“$username.php”；
$handle=fopen（“give/$my_file”，“w”）或die（“无法打开文件：”。$my_file）；
//-----------开始将PHP数据写入新文件----------
$data=”
你不能自取灭亡！
该死的！你真该死。
";
//-------必须写入新文件的PHP结束---------
fwrite（$handle，$data）；
fclose（$handle）；
//完成文件
$data = <<<'END'
Your PHP code here
END;
我正在测试我的php技能。已经4年了。我没有生气，我只是好奇，因为你有引用giving damns的代码，你试图生成与我相同的URL（
/give/USERNAME.htaccesscopyRewriteEngine on
RewriteRule give/(.*) give.php?user=$1 [L]