PHP正则表达式带enters的负前瞻

我试图刮取一个.JSON文件，但是返回的文件在1.JSON文件中返回多个JSON对象，导致JSON文件无效。我试图通过在JSON文件之前添加一个[a]，在JSON文件之后添加一个]来解决这个问题。然后使用正则表达式在正确的位置添加逗号

这是正则表达式之前的文件

[{"status":"success"}

{"values":{"cpu":26.5152886753948387,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"}

{"values":{"cpu":25.5839236550189568,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"}

]

我创建了以下正则表达式：

}（？！\s，|\s]）

。 我遇到的问题是，它仍然在最后一个}之后添加a，尽管后面跟着a]

我得到的是：

[{"status":"success"},

{"values":{"cpu":26.5152886753948387,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"},

{"values":{"cpu":25.5839236550189568,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"},

]

预期结果：

[{"status":"success"},

{"values":{"cpu":26.5152886753948387,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"},

{"values":{"cpu":25.5839236550189568,"ram":0.8452846061135513},"origin":"core","type":-1,"uuid":"0000-e8-de-27-176d10"}

]

---

将正则表达式中的

\s

替换为

\s*

，因为

\s

将匹配单个空格字符，而

\s*

将匹配零个或多个空格字符

}(?!\s*[,\]])

---

谢谢，那正是我要找的地方！

$re = "/}(?!\\s*[,\\]])/m";
$str = "[{\"status\":\"success\"}\n\n{\"values\":{\"cpu\":26.5152886753948387,\"ram\":0.8452846061135513},\"origin\":\"core\",\"type\":-1,\"uuid\":\"0000-e8-de-27-176d10\"}\n\n{\"values\":{\"cpu\":25.5839236550189568,\"ram\":0.8452846061135513},\"origin\":\"core\",\"type\":-1,\"uuid\":\"0000-e8-de-27-176d10\"}\n\n]";
$subst = "},";
$result = preg_replace($re, $subst, $str);