PHP:Laravel查询优化
我有一个PHP:Laravel查询优化,php,mysql,database,laravel-5,optimization,Php,Mysql,Database,Laravel 5,Optimization,我有一个query,即通过一个包含30多万条记录的表进行查询。下面是Laravel 5.5中的查询: $this->select = \DB::table('transport_orders') ->join('users', 'users.id', '=', 'transport_orders.user_id', 'left') ->join('transport_order_price_requests', 'transport_order_price_requ
query
,即通过一个包含30多万条记录的表进行查询。下面是Laravel 5.5中的查询:
$this->select = \DB::table('transport_orders')
->join('users', 'users.id', '=', 'transport_orders.user_id', 'left')
->join('transport_order_price_requests', 'transport_order_price_requests.transport_order_id', '=', 'transport_orders.id', 'left')
->join('price_requests', 'transport_order_price_requests.price_request_id', '=', 'price_requests.id', 'left')
->join('order_numbers', 'transport_orders.order_number_id', '=', 'order_numbers.id', 'left')
->join(\DB::raw('
(select transport_order_statuses.transport_order_id, max(transport_order_statuses.id) as last_link_id
from transport_order_statuses
group by transport_order_statuses.transport_order_id) as last_statuses'
), function ($join) {
$join->on('transport_orders.id', '=', 'last_statuses.transport_order_id');
})
->join('transport_order_statuses', 'last_statuses.last_link_id', '=', 'transport_order_statuses.id')
->join('statuses', 'transport_order_statuses.status_id', '=', 'statuses.id')
->select(
'transport_orders.id as id',
\DB::raw('CONCAT(users.first_name, \' \', users.last_name) as user_full_name'),
\DB::raw('DATE_FORMAT(transport_orders.pickup_date , "%Y-%m-%d") as pickup_date'),
'transport_orders.location_name',
'transport_orders.carrier_name',
'transport_orders.country_name',
'transport_orders.country_code',
'transport_orders.category_name',
'transport_orders.zip',
'transport_orders.rate_type',
'transport_orders.rate_name',
'transport_orders.order_number_id',
'order_numbers.order_number as order_number',
'transport_orders.comment',
'transport_orders.inbound',
'transport_orders.unit',
'transport_orders.unit_value',
\DB::raw('DATE_FORMAT(transport_orders.created_at , "%Y-%m-%d") as created_at'),
'transport_orders.base_price',
'transport_orders.created_at',
'transport_orders.updated_at',
'transport_orders.price',
'transport_orders.stops',
'transport_orders.stop_price',
'transport_orders.id as id',
'transport_orders.transport_mode as transport_mode_name',
'statuses.status as status',
'statuses.id as status_id',
'transport_orders.multishipment as multishipment',
'transport_orders.total_weight as total_weight',
'order_numbers.simulation as simulated'
)->where('transport_orders.is_deleting', '=', 0);
在此之后,我会:
$this->select->paginate($itemsPerPage);
现在,如果要将此查询
转换为普通的MySql
,那么它就是:
select `transport_orders`.`id` as `id`,
CONCAT(users.first_name, ' ', users.last_name) as user_full_name,
DATE_FORMAT(transport_orders.pickup_date , "%Y-%m-%d") as pickup_date,
`transport_orders`.`location_name`, `transport_orders`.`carrier_name`,
`transport_orders`.`country_name`, `transport_orders`.`country_code`,
`transport_orders`.`category_name`, `transport_orders`.`zip`,
`transport_orders`.`rate_type`, `transport_orders`.`rate_name`,
`transport_orders`.`order_number_id`, `order_numbers`.`order_number` as `order_number`,
`transport_orders`.`comment`, `transport_orders`.`inbound`, `transport_orders`.`unit`,
`transport_orders`.`unit_value`,
DATE_FORMAT(transport_orders.created_at , "%Y-%m-%d") as created_at,
`transport_orders`.`base_price`, `transport_orders`.`created_at`,
`transport_orders`.`updated_at`, `transport_orders`.`price`, `transport_orders`.`stops`,
`transport_orders`.`stop_price`, `transport_orders`.`id` as `id`,
`transport_orders`.`transport_mode` as `transport_mode_name`,
`statuses`.`status` as `status`, `statuses`.`id` as `status_id`,
`transport_orders`.`multishipment` as `multishipment`,
`transport_orders`.`total_weight` as `total_weight`, `order_numbers`.`simulation` as `simulated`
from `transport_orders`
left join `users` ON `users`.`id` = `transport_orders`.`user_id`
left join `transport_order_price_requests` ON `transport_order_price_requests`.`transport_order_id` = `transport_orders`.`id`
left join `price_requests` ON `transport_order_price_requests`.`price_request_id` = `price_requests`.`id`
left join `order_numbers` ON `transport_orders`.`order_number_id` = `order_numbers`.`id`
inner join
(
SELECT transport_order_statuses.transport_order_id, max(transport_order_statuses.id) as last_link_id
from transport_order_statuses
group by transport_order_statuses.transport_order_id
) as last_statuses ON `transport_orders`.`id` = `last_statuses`.`transport_order_id`
inner join `transport_order_statuses` ON `last_statuses`.`last_link_id` = `transport_order_statuses`.`id`
inner join `statuses` ON `transport_order_statuses`.`status_id` = `statuses`.`id`
where `transport_orders`.`is_deleting` = 0
and `order_numbers`.`simulation` = 0
order by `transport_orders`.`created_at` desc
limit 13 offset 0
Laravel
debugbar
告诉我查询花费的时间超过了9秒。当我使用paginate
(Length-Aware-Paginator
)时,它也会进行计数,因此需要大约6秒的时间。当我在MySql
中运行普通查询时,也需要9-10秒。如何优化此查询?请注意,我不想使用simplePaginate
,因为它需要大量重构。这些索引可能会有帮助:
transport_order_statuses: (transport_order_id, id)
transport_orders: (is_deleting, created_at)
transport_order_price_requests: (transport_order_id, price_request_id)
将所有左连接
更改为连接
可以提供相同的答案,同时为优化器提供更多选项(并减少混淆)
由于在WHERE
中引用了两个表,因此在通过和LIMIT
获得订单之前,可能必须通过WHERE
完成查询评估,因此不允许在此区域进行任何优化。去除simulation=0
可能会加快速度(以获取太多行为代价)。只是为了观察,日期是“%Y-%m-%d”,因此日期格式(…%Y-%m-%d”)要么是冗余的,要么是与日期相同的(…)