PHP-在嵌套的foreach循环中取消设置对象

所以长话短说-在第一个foreach中尝试取消设置$this->models[$modelKey]时，取消设置工作正常，$this->models[$modelKey]->equipmentList->equipment[$eqKey]指向正确的对象，但在嵌套的foreach中取消设置不起作用。有什么想法吗？提前谢谢你的帮助

public function processModelsEquipmentList() {
    foreach ($this->models as $modelKey => $model) {
      if (!strstr('#', $model->id)) {
        foreach ($model->equipmentList->equipment as $eqKey => $equipment) {
          if (in_array($equipment->code, $this->specialVersionsCodes)) {
            $newModel = clone $model;   
            $newModel->name.= ' ' . $equipment->name;
            $newModel->id.= '#' . $equipment->id;
            if (strlen($newModel->code) < 4) {
              $newModel->code.=$equipment->code;
            }
            $newModel->order = $newModel->order + 1;
            $newEquipmentList = new EquipmentList($newModel->id, true);
            $newEquipmentList->add(clone $equipment);
            $newModel->setNewEquipmentList($newEquipmentList);
            $this->addModel($newModel);
            //echo $this->models[$modelKey]->equipmentList->equipment[$eqKey]->name;die();
            unset($this->models[$modelKey]->equipmentList->equipment[$eqKey]);
          }
        }
      }
    }
  }

---

它不是通过$model而不是$this->models访问的吗？同样的设备

试试这个：

unset($equipment[$eqKey]); 

一些扩展：

foreach ($this->models as $modelKey => $model) {
    //here you use $model to access $this->models[X]
    foreach ($model->equipmentList->equipment as $eqKey => $equipment) { 
        //here you use $equipment to access $this->models[X]->equipmentList->equipment[x]
    } 
} 

编辑：

现在我得到了解决方案：

foreach ($this->models as $modelKey => $model) {
    foreach ($model->equipmentList->equipment as $eqKey => $equipment) {
        //use the $modelKey key and not the $eqKey
        unset($model->equipmentList->equipment[$modelKey]);
    } 
} 

---

如果我说得对，我会回答这个问题，但如果我错了，我会把这个问题转移到评论：

首先，克隆最后要取消设置的对象。为什么不在克隆后立即取消设置呢

其次，我认为该对象是通过设计通过引用传递给foreach循环的，因此不需要引用键

如果我是对的，这可能有用：

public function processModelsEquipmentList() {
    foreach ($this->models as $modelKey => $model) {
      if (!strstr('#', $model->id)) {
        foreach ($model->equipmentList->equipment as $eqKey => $equipment) {
          if (in_array($equipment->code, $this->specialVersionsCodes)) {
            $newModel = clone $model;
            unset($model);  // <-- Unesetting after clone, using loop var name.
            $newModel->name.= ' ' . $equipment->name;
            $newModel->id.= '#' . $equipment->id;
            if (strlen($newModel->code) < 4) {
              $newModel->code.=$equipment->code;
            }
            $newModel->order = $newModel->order + 1;
            $newEquipmentList = new EquipmentList($newModel->id, true);
            $newEquipmentList->add(clone $equipment);
            $newModel->setNewEquipmentList($newEquipmentList);
            $this->addModel($newModel);
          }
        }
      }
    }
  }

---

已尝试：未设置$设备；，取消设置$model->equipmentList->equipment[$eqKey]；-这两种解决方案都不起作用$equipment是一个对象，因此$equipment[$eqKey]不准确。同时使用对这些对象的引用-在这样做时不会改变任何事情：foreach$model->equipmentList->equipment as$eqKey=>&$equipment，在foreach$this->models as$modelKey=>&$model上执行时内存不足。是否要取消设置对象或对象的属性？我正在尝试取消设置保存在数组中的对象。为了澄清：$this->models-Array，$model->equipmentList-object，$model->equipmentList->equipment-Array-of-objects您在第一条评论中写道您尝试取消设置$equipment；对象数组，但未取消设置$equipment[$eqKey]；objectforeach$model->equipmentList->equipment作为$eqKey=>$equipment-$equipment是一个对象，$model->equipmentList->equipment是一个数组。我的名字不好P1。我想取消设置$equipment，而不是$model。2.关于参考资料的想法来自这里。他们说如果我想用这种方式解决问题，我需要使用它。3.在$newEquipmentList->addclone$equipment之后移动取消设置；没有改变任何事情。编辑：粘贴了错误的链接。现在它是正确的