Php 如何在mysqli prepare语句中插入pourcentage符号%？

我想运行下面的代码：

但它显示了一个错误

$stmt = $this->con->prepare("SELECT HEUREDEB , HEUREFIN from reservation 
where ID_EMPL = ? and HEUREDEB like ?%");
            $stmt->bind_param("ss",$ID_EMPL,$HEUREDEB);
            $stmt->execute();
            $result=$stmt->get_result();

使用CONCAT

您也可以将其添加到变量中

$HEUREDB .= '%';
$stmt = $this->con->prepare("SELECT HEUREDEB , HEUREFIN from reservation 
where ID_EMPL = ? and HEUREDEB like ?");

$HEUREDB .= '%';
$stmt = $this->con->prepare("SELECT HEUREDEB , HEUREFIN from reservation 
where ID_EMPL = ? and HEUREDEB like ?");