计算PHP数组中值的出现次数

我已将SQL查询的结果加载到数组中。字段为ComputerName、时间（以天为单位）、房间、键入ComputerName

我想知道每天发生多少次

数组的示例值为：

[STU-CZC1087SNC] => Array
    (
        [ComputerName] => STU-CZC1087SNC
        [time_in_days] => 0
        [room] => 4Q08
    )

[STU-CZC02501QT] => Array
    (
        [ComputerName] => STU-CZC02501QT
        [time_in_days] => 12
        [room] => 2R017
    )

所以我想知道有多少台计算机的时间为12天，有多少台计算机的时间为0天

它将用于绘制图形

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我该怎么做/最好的方法是什么？

可能是数组计数值，请参阅手册：

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试试这个，其中$input是包含计算机数据的数组：

$result = array();
foreach($input as $computerName => $arr){
  if(!isset($result[ $arr['time_in_days'] ]))
    $result[ $arr['time_in_days'] ] = 0;
  $result[ $arr['time_in_days'] ]++;
}
return $result;

结果将类似于：

[
  12 => 2, //2 computers have time_in_days of 12
  0 => 1  //1 computer has time_in_days of 0
]

---

好的，下面是一个工作示例：

<?php

$computerarray = [
'STU-CZC1087SNC' => Array
(
    'ComputerName' => 'STU-CZC1087SNC',
    'time_in_days' => 0,
    'room' => '4Q08'
),

'STU-CZC02501QT' => Array
(
    'ComputerName' => 'STU-CZC02501QT',
    'time_in_days' => 12,
    'room' => '2R017'
),
'STU-CZC02501QF' => Array
(
    'ComputerName' => 'STU-CZC02501QT',
    'time_in_days' => 12,
    'room' => '2R017'
)    
];


$myarray = array();
foreach($computerarray as $key => $val){
    $myarray[] = $val['time_in_days'];
}

echo "<pre>";
$myarray = array_count_values($myarray);
print_r($myarray);

此代码计算圆内的成员数。它将成员表id与当前圆圈id匹配。其当前值为$c['id']=1

$computerarray = [
    'STU-CZC1087SNC' => ['ComputerName' => 'STU-CZC1087SNC','time_in_days' => 0,'room' => '4Q08'],
    'STU-CZC02501QT' => ['ComputerName' => 'STU-CZC02501QT','time_in_days' => 12,'room' => '2R017'],
    'STU-CZC02501QF' => ['ComputerName' => 'STU-CZC02501QT','time_in_days' => 12,'room' => '2R017']    
];

var_export(array_count_values(array_column($computerarray,'time_in_days')));

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我将删除我对以下问题的评论：

最好的方法是不使用php，而是使用sql按时间和调用计数进行分组。这里有一个推进去的

对于无条件、功能性的方法，这里是一个单行程序，使用专门为此任务设计的两个功能：和

代码：

输出：

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与我的回答几乎相同，使用此代码您将收到大量通知。只需添加错误报告0；防止这些-P+1分。。我花了很长时间才明白：我不认为这是OP要求的通用解决方案。当计算机数据中有任意数字时，这不起作用。例如time_in_days=15和time_in_days=2等@MarkBaker请改进此仅限代码的答案，并稍加解释。使用此仅限代码的答案稍加解释将有助于未来的读者。我建议使用if/else，因为如果if为真，您将写入0，然后立即覆盖到1。如果…{…=1}或者{++}我真的更喜欢这样。在我看来，可读性/可理解性更好的代码是：总是递增1。和功能分离：如果未设置，则初始化该值。

<?php

$computerarray = [
'STU-CZC1087SNC' => Array
(
    'ComputerName' => 'STU-CZC1087SNC',
    'time_in_days' => 0,
    'room' => '4Q08'
),

'STU-CZC02501QT' => Array
(
    'ComputerName' => 'STU-CZC02501QT',
    'time_in_days' => 12,
    'room' => '2R017'
),
'STU-CZC02501QF' => Array
(
    'ComputerName' => 'STU-CZC02501QT',
    'time_in_days' => 12,
    'room' => '2R017'
)    
];


$myarray = array();
foreach($computerarray as $key => $val){
    $myarray[] = $val['time_in_days'];
}

echo "<pre>";
$myarray = array_count_values($myarray);
print_r($myarray);

$total = null; 
foreach ($members as $owner): 
    if($owner['circle_id'] == $c['id']): // or if($owner['circle_id'] == 1):
        $total = $total + 1;
    endif;
endforeach;
echo $total;

$my_arr = Array();
array_walk($arr, function($v) use(&$my_arr) {$my_arr[] = $v['time_in_days'];});
$time_freq = array_count_values($my_arr);
var_dump($time_freq);
/**
  OUTPUT
**/
array
  0 => int 1
  12 => int 2

$computerarray = [
    'STU-CZC1087SNC' => ['ComputerName' => 'STU-CZC1087SNC','time_in_days' => 0,'room' => '4Q08'],
    'STU-CZC02501QT' => ['ComputerName' => 'STU-CZC02501QT','time_in_days' => 12,'room' => '2R017'],
    'STU-CZC02501QF' => ['ComputerName' => 'STU-CZC02501QT','time_in_days' => 12,'room' => '2R017']    
];

var_export(array_count_values(array_column($computerarray,'time_in_days')));

array (
  0 => 1,
  12 => 2,
)