如何在php中显示时差
我想以时差的形式显示这些数据，比如2分钟前，2天前 我的代码没有显示正确的时间，而且它在所有发布的数据中显示相同的时间如何在php中显示时差,php,Php,我想以时差的形式显示这些数据，比如2分钟前，2天前 我的代码没有显示正确的时间，而且它在所有发布的数据中显示相同的时间 <?php $conn = new mysqli("localhost","root","","blog_samples"); $sql="UPDATE comments SET status=1 WHERE status=0"; $result=mysqli_query($conn, $sql); try{ $
<?php
$conn = new mysqli("localhost","root","","blog_samples");
$sql="UPDATE comments SET status=1 WHERE status=0";
$result=mysqli_query($conn, $sql);
try{
$con = new PDO("mysql:host=localhost;dbname=blog_samples",'root','');
$sth = $con->prepare( "SELECT * FROM `comments` ORDER BY id DESC limit 5");
$sth->setFetchMode(PDO:: FETCH_OBJ);
$sth->execute();
while($row=$sth->fetch()){
?>
<li>
<a href="javascript:void(0)">
<span class="label label-primary"><i class="fa fa-user"></i></span>
<span class="message"> New POST</span>
<span class="time"><?php
$tim = $row->samay;
$date1 = strtotime($tim);
$date2 = strtotime(date('Y-m-d H:i:s'));
$seconds_diff = $date2 - $date1;
echo round(abs($seconds_diff) / 60,2). " mins ago";
?></span>
</a>
</li>
<?php } }
catch(PDOEception $e){
echo "Error: ". $e->getMessage();
}
?>
function timeAgo($time_ago) {
$time_ago = strtotime($time_ago);
$cur_time = time();
$time_elapsed = $cur_time - $time_ago;
$seconds = $time_elapsed;
$minutes = round($time_elapsed / 60);
$hours = round($time_elapsed / 3600);
$days = round($time_elapsed / 86400);
$weeks = round($time_elapsed / 604800);
$months = round($time_elapsed / 2600640);
$years = round($time_elapsed / 31207680);
// Seconds
if ($seconds <= 60) {
return "$seconds seconds ago";
} //Minutes
else if ($minutes <= 60) {
if ($minutes == 1) {
return "one minute ago";
} else {
return "$minutes minutes ago";
}
} //Hours
else if ($hours <= 24) {
if ($hours == 1) {
return "an hour ago";
} else {
return "$hours hours ago";
}
} //Days
else if ($days <= 7) {
if ($days == 1) {
return "yesterday";
} else {
return "$days days ago";
}
} //Weeks
else if ($weeks <= 4.3) {
if ($weeks == 1) {
return "a week ago";
} else {
return "$weeks weeks ago";
}
} //Months
else if ($months <= 12) {
if ($months == 1) {
return "a month ago";
} else {
return "$months months ago";
}
} //Years
else {
if ($years == 1) {
return "one year ago";
} else {
return "$years years ago";
}
}
}
函数timeAgo（$time\u ago）{
$time\u ago=strottime（$time\u ago）；
$cur_time=time（）；
$time\u appeased=$cur\u time-$time\u ago；
$seconds=$time\u经过的时间；
$minutes=round（$time_passed/60）；
$hours=整数（$time\u appead/3600）；
$days=round（$time_passed/86400）；
$weeks=整数（$time_passed/604800）；
$months=round（$time_passed/2600640）；
$years=round（$time_passed/31207680）；
//秒
如果（$seconds，则此函数将在一段时间前返回：
<?php
function get_timeago( $ptime )
{
$estimate_time = time() - $ptime;
if( $estimate_time < 1 )
{
return 'less than 1 second ago';
}
$condition = array(
12 * 30 * 24 * 60 * 60 => 'year',
30 * 24 * 60 * 60 => 'month',
24 * 60 * 60 => 'day',
60 * 60 => 'hour',
60 => 'minute',
1 => 'second'
);
foreach( $condition as $secs => $str )
{
$d = $estimate_time / $secs;
if( $d >= 1 )
{
$r = round( $d );
return 'about ' . $r . ' ' . $str . ( $r > 1 ? 's' : '' ) . ' ago';
}
}
}
?>
这是显示数据代码
<?php
include('functions.php');
$conn = new mysqli("localhost","root","","blog_samples");
$sql="UPDATE comments SET status=1 WHERE status=0";
$result=mysqli_query($conn, $sql);
try
{
$con = new PDO("mysql:host=localhost;dbname=blog_samples",'root','');
$sth = $con->prepare( "SELECT * FROM `comments` ORDER BY id DESC limit 5");
$sth->setFetchMode(PDO:: FETCH_OBJ);
$sth->execute();
while($row=$sth->fetch())
{
?>
<li>
<a href="javascript:void(0)">
<span class="label label-primary"><i class="fa fa-user"></i></span>
<span class="message"> New POST</span>
<span class="time"><?php
echo timeAgo(date("Y-m-d H:i:s"));
?>
</span>
</a>
</li>
<?php } }
catch(PDOEception $e){
echo "Error: ". $e->getMessage();
}
?>
这是functions.php
<?php
function timeAgo($time_ago) {
$time_ago = strtotime($time_ago);
$cur_time = time();
$time_elapsed = $cur_time - $time_ago;
$seconds = $time_elapsed;
$minutes = round($time_elapsed / 60);
$hours = round($time_elapsed / 3600);
$days = round($time_elapsed / 86400);
$weeks = round($time_elapsed / 604800);
$months = round($time_elapsed / 2600640);
$years = round($time_elapsed / 31207680);
// Seconds
if ($seconds <= 60) {
return "$seconds seconds ago";
} //Minutes
else if ($minutes <= 60) {
if ($minutes == 1) {
return "one minute ago";
} else {
return "$minutes minutes ago";
}
} //Hours
else if ($hours <= 24) {
if ($hours == 1) {
return "an hour ago";
} else {
return "$hours hours ago";
}
} //Days
else if ($days <= 7) {
if ($days == 1) {
return "yesterday";
} else {
return "$days days ago";
}
} //Weeks
else if ($weeks <= 4.3) {
if ($weeks == 1) {
return "a week ago";
} else {
return "$weeks weeks ago";
}
} //Months
else if ($months <= 12) {
if ($months == 1) {
return "a month ago";
} else {
return "$months months ago";
}
} //Years
else {
if ($years == 1) {
return "one year ago";
} else {
return "$years years ago";
}
}
}
?>
所有时间之前都显示相同@Akshay komarla请设置可读性格式改进格式如何调用此函数@Akshay komarlatimeAgo（日期（“Y-m-d H:i:s”））
只需传递所需的日期和时间编辑所有post的GIV相同输出@Akshay komarlait在所有发布的数据@Milan Chheday中显示相同的时间前你只需发送时间..示例：1516789440..或echo get_timeago（time（））；
你需要传递所需的日期时间。如果你传递echo timeago（日期（“Y-m-d H:i:s”））
它将给出相同的值，因为日期（“Y-m-d H:i:s”）
将给出当前日期时间。例如：echo timeAgo（日期（“2018-01-23 12:12:12”）；像这样使用我获取发布的时间。但它给出相同的输出首先查看ur$times变量打印的格式，然后传递给函数