Php mysqli_fetch_array（）希望参数1是mysqli_结果-需要帮助ssss

mysqli_fetch_数组期望参数1为mysqli_结果，给定布尔值-

$query = "SELECT type, SUM(price) FROM products GROUP BY type";

$result=mysqli_query($db, $query);


while($row = mysqli_fetch_array($result)){
    echo "Total ". $row['type']. " = $". $row['SUM(price)'];

}

用作：

$query = "SELECT type, SUM(price) as sums FROM products GROUP BY type";
$result=mysqli_query($db, $query);
while($row = mysqli_fetch_array($result))
{
echo "Total ". $row['type']. " = $". $row['sums'];
}

首先，检查$db标识符，在哪里定义连接？若连接正常，则需要使用mysqli\u error检查查询错误

您应该检查$result参数：

$query = "SELECT type, SUM(price) FROM products GROUP BY type";

$result=mysqli_query($db, $query);

if($result === FALSE) { 
    printf("Error: %s\n", mysqli_error($db)); // TODO: better error handling
}    

while($row = mysqli_fetch_array($result)){
    echo "Total ". $row['type']. " = $". $row['SUM(price)'];

}

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您的查询不工作，可能是查询有问题，也可能是您的连接有问题。