Php jQuery从多维数组获取数据

我从mysql表中获取多维数组中的数据。所以数据是这样的

Array
(
    [0] => stdClass Object
        (
            [id] => 2
            [client_id] => 2
            [first_name] => test1
            [last_name] => test2
        )

    [1] => stdClass Object
        (
            [id] => 3
            [client_id] => 2
            [first_name] => test3
            [last_name] => test4
        )

)

[{"id":"2","client_id":"2","first_name":"test1","last_name":"test2"},
{"id":"3","client_id":"2","first_name":"test3","last_name":"test4"}]

data = $.parseJSON(data);

因为我需要json格式的数据，所以我这样做 json_编码（$users）

它给了我这样的结果

Array
(
    [0] => stdClass Object
        (
            [id] => 2
            [client_id] => 2
            [first_name] => test1
            [last_name] => test2
        )

    [1] => stdClass Object
        (
            [id] => 3
            [client_id] => 2
            [first_name] => test3
            [last_name] => test4
        )

)

[{"id":"2","client_id":"2","first_name":"test1","last_name":"test2"},
{"id":"3","client_id":"2","first_name":"test3","last_name":"test4"}]

data = $.parseJSON(data);

因为我想在对象中获取数据，所以我这样做了

Array
(
    [0] => stdClass Object
        (
            [id] => 2
            [client_id] => 2
            [first_name] => test1
            [last_name] => test2
        )

    [1] => stdClass Object
        (
            [id] => 3
            [client_id] => 2
            [first_name] => test3
            [last_name] => test4
        )

)

[{"id":"2","client_id":"2","first_name":"test1","last_name":"test2"},
{"id":"3","client_id":"2","first_name":"test3","last_name":"test4"}]

data = $.parseJSON(data);

---

这给了我两个对象中的数据。现在我想获取第一个名字的数据。有人能告诉我怎么做吗？

数据[i]['first\u name']

会告诉你名字。在i

上使用循环迭代在

JS

变量中成功添加数据后，您可以通过for look获得

first\u name

，如下所示

for(var i=0; i < data.length; i++){
  console.log(data[i].first_name)
}

for（变量i=0；i

您需要使用jQuery

每个功能。例如，以下代码可能会帮助您：

var obj = 
        [{"id":"2","client_id":"2","first_name":"test1","last_name":"test2"},
        {"id":"3","client_id":"2","first_name":"test3","last_name":"test4"}];

        $.each(obj,function(i,o){
            alert(o.id);
        }); 

如果您在寻找其他内容，请告诉我：）
。jquery中的每个（（）函数？？是的..但是如何处理多维数组。。