Php 使用JOIN链接表

我有三张桌子； 成员ID、成员、个人

我需要“会员”的名字和姓氏 “MemberID”中的MemberID和PersonID 下面给我一张名单

   SELECT 
   CONCAT(P.FirstName, ' ', P.LastName) as FullName
   FROM `membership` M
   INNER JOIN `memberID` MI ON M.`MembershipID` = MI.`MembershipID`
   INNER JOIN `person` P ON MI.`PersonID` = P.`PersonID`
   AND P.`IsActive` =1

以下操作失败，如何添加PersonID和MembershipID列。 我相信我需要另一个内部连接，但我不知道如何构造它

   SELECT
   CONCAT(P.FirstName, ' ', P.LastName) as FullName
   FROM `membership` M
   MI.'membershipID' MI.'PersonID' FROM  'membershipID' MI
   INNER JOIN `memberID` MI ON M.`MembershipID` = MI.`MembershipID`

   INNER JOIN `person` P ON MI.`PersonID` = P.`PersonID`
   AND P.`IsActive` =1

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假设这些列已经在被引用的表中：

SELECT CONCAT(P.FirstName, ' ', P.LastName) as FullName,
       MI.PersonID, M.`MembershipID`
FROM `membership` M INNER JOIN
     `memberID` MI
     ON M.`MembershipID` = MI.`MembershipID` INNER JOIN
     `person` P
     ON MI.`PersonID` = P.`PersonID` AND P.`IsActive` = 1;

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您不需要额外的联接，只需在

选择中添加列即可。。谢谢