从索引的PHP数组中检索相同的值

我正在做一个发票到采购订单模块。比如说在一张发票里有3种产品

Product a => Vendor A 
Product b => Vendor B
Product c => Vendor A

我有一个从angularJS传递到PHP的数组

该数组称为

 products

下面的代码在我的PHP页面中

$products = isset($post_data['products']) ? $post_data['products']:array();

if(count($products) > 0){
    foreach($products as $v){
         //following code is working, but it will create 3 new PO with 
         //the respective products. So if let's say there are 3 products, with 2 items with same vendor, and 1 with another vendor, 
         //it will insert 3 new PO. What I wanted is to create 1 PO with 2 items(same vendor), 1 another PO with different vendor
         $param = array(
            //po data to insert
         );
         $this->_model->add($param);
         $insert_id = $this->db->insert_id();

         $products_array = array(
           //purchased product
         );
         $this->generic_model->add($products_array);        
    }
}

下面是从数组传递到PHP页面的var_dump结果（从var_dump（$v））

从var_转储结果中可以看到，有两个相同的供应商，它们是供应商2

所以我的问题是，如何在PHP中循环angularJS中的数组，然后基于同一供应商对其进行“分组”？在前面的示例中，如何使用以下数据将数据插入数据库

2 tables in my db, purchase_order and purchased_product
New PO with 2 items inside from Vendor 2, (1 purchase order row with 2 rows in purchased_product)
Another new PO with 1 item from Vendor 1, (1 purchase order row with 1 row in purchased_product)

已经处理了很长一段时间，仍然不知道如何进行数组循环

---

谢谢……）

您的代码示例没有说明从何处获得

PO 1

和

PO 2

密钥，因此我无法将其包含在解决方案中。请随时更新您的问题，以澄清这一点

要采用如上所述的JSON结构并将其转换为指定的“分组”字符串值数组，可以尝试以下操作：

<?php

// firstly, just some boilerplate for this example

$json = <<<JSON
[
    {
       "id": "35",
       "vendor": "Vendor 1",
       "vendor_id": "5"
    },
    {
       "id": "33",
       "vendor": "Vendor 2",
       "vendor_id": "7"
    },
    {
       "id": "34",
       "vendor": "Vendor 2",
       "vendor_id": "7"
    }
]
JSON;

$data = json_decode($json, true); 

// now we can start extracting and grouping data

// assuming you are using >= 5.5 here
// `array_column()` extracts the values of all 
// sub-arrays with the `vendor` key into an array
$vendors = array_column($data, 'vendor');

// `array_count_values()` aggregates a count
// for each instance of each string in the array
// with the vendor as the key and a count as its corresponding value
$vendorCounts = array_count_values($vendors);

// map over the keys and values, creating an array
// of strings in the specified format
$vendorGroups = array_map(function ($vendor, $count) {
    return sprintf('%d items from %s', $count, $vendor);
}, array_keys($vendorCounts), $vendorCounts);

print_r($vendorGroups);

文件参考：

---

希望这有帮助：）

您可以在JS（客户端）端对供应商进行分组。此外，展示如何查看将数据插入数据库的//代码从何处获得

PO 1

和

PO 2

？更新的说明和代码：）。如果我不能很好地解释，请原谅我，我是一名初级程序员，仍在研究如何编写代码..先生，更新了问题并删除了JSON。我用（$v）中的var_dump替换它，希望它能更清楚地理解

<?php

// firstly, just some boilerplate for this example

$json = <<<JSON
[
    {
       "id": "35",
       "vendor": "Vendor 1",
       "vendor_id": "5"
    },
    {
       "id": "33",
       "vendor": "Vendor 2",
       "vendor_id": "7"
    },
    {
       "id": "34",
       "vendor": "Vendor 2",
       "vendor_id": "7"
    }
]
JSON;

$data = json_decode($json, true); 

// now we can start extracting and grouping data

// assuming you are using >= 5.5 here
// `array_column()` extracts the values of all 
// sub-arrays with the `vendor` key into an array
$vendors = array_column($data, 'vendor');

// `array_count_values()` aggregates a count
// for each instance of each string in the array
// with the vendor as the key and a count as its corresponding value
$vendorCounts = array_count_values($vendors);

// map over the keys and values, creating an array
// of strings in the specified format
$vendorGroups = array_map(function ($vendor, $count) {
    return sprintf('%d items from %s', $count, $vendor);
}, array_keys($vendorCounts), $vendorCounts);

print_r($vendorGroups);

Array
(
    [0] => 1 items from Vendor 1
    [1] => 2 items from Vendor 2
)