Php 如何在zend framework中进行多文件上传

我想实现多文件上传。我得到这个代码只有一个文件正在上传。如何实现多文件上传

表格代码

$docupload=new Zend_Form_Element_File('docupload',array('multiple' => 'multiple'));
                $docupload->addValidator(new Zend_Validate_File_Extension('doc,docx,pdf,txt'));
                $docupload->setIsArray(true);

在控制器中

if(is_array($_FILES['docupload']['name']))
                {

                    $params = $this->_form->getValues();
                    foreach($_FILES['docupload']['name'] as $key=>$files)
                    {

                        $file_name=$_FILES['docupload']['name'][$key];
                       $temp_image_path = $_FILES['docupload']['tmp_name'][$key];

                     $file_name=implode(",", $file_name);
                    $temp_image_path=implode(",", $temp_image_path);
                    ['tmp_name'];
                    $path_parts = pathinfo($temp_image_path);

                    $tem_path =   $path_parts['dirname'];

                    $path_parts_extension = pathinfo($file_name);


                    $actual_filename=$path_parts_extension['filename'];
                    $file_extension = $path_parts_extension['extension'];



                if(APPLICATION_ENV != "development")
                    {
                        $path = '/';
                    }
                    else {

                        $path = '\\';
                    }

                    $filename = $tem_path.$path.$file_name;

                    $rename_uploadfile = $actual_filename.$random_number.".".$file_extension;

                    $fullFilePath = UPLOAD_USER_IMAGES.$rename_uploadfile;

                    // Rename uploaded file using Zend Framework
                    $filterFileRename = new Zend_Filter_File_Rename(array('target' => $fullFilePath));
                    $filterFileRename->filter($filename);
                    $form_data=$params;
                    $form_data['docupload']=$rename_uploadfile;

                    if($id)
                    {
                        $this->_table->updateById("id",$id, $form_data);

                    }
                    else 
                    {
                    $this->_table->insert($form_data);  
                    }

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我是zend框架的新手。请帮助我。请提前感谢

与其使用$\u FILES变量，不如使用适用的Zend代码，因为您正在使用Zend作为您的框架：

if (!$form->isValid()) {
    print "Uh oh... validation error";
}

if (!$form->docupload->receive()) {
    print "Error receiving the file(s)";
}

$files = $form->docupload->getFileName(); // result should be an array in this case

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我加了那句话。但有时上传，有时不上传。有什么问题？