Php mysql |嵌套设置为选择框

我有嵌套的集合表（Joomla类别表）：

如何将此数据转换为选择框

<select>
   <option value="12">Category1</option>
   <option value="13">...Category2</option>
</select>  

类别1
…类别2

$query=mysql\u query（'select*from table'）；
//首先选择您的表
回声“；
//在while循环中执行以下代码。。
while（$row=mysql\u fetch\u array（$query））
{
回显“$row['title']”；
}
回声“；

这是一个正确的答案：

$sql = ' SELECT node.id, CONCAT( REPEAT( "...", (COUNT(parent.title) - 2)), node.title) AS title
                        FROM    `#__categories` AS node,
                                `#__categories` AS parent
                        WHERE node.lft BETWEEN parent.lft AND parent.rgt
                        GROUP BY node.title
                        ORDER BY node.lft';

---

谢谢但是您的代码返回：Category1 Category2

  $query= mysql_query('select * from table');
   //select your table first

   echo "<select>";
 // and in your while loop do this code.. 
   while($row = mysql_fetch_array($query))
    {
        echo "<option value=".$row['id']. " > ". $row['title'] ."</option>";
    }
   echo "</select>";

$sql = ' SELECT node.id, CONCAT( REPEAT( "...", (COUNT(parent.title) - 2)), node.title) AS title
                        FROM    `#__categories` AS node,
                                `#__categories` AS parent
                        WHERE node.lft BETWEEN parent.lft AND parent.rgt
                        GROUP BY node.title
                        ORDER BY node.lft';