Php 如何正确格式化JSON Laravel 5.5
我正在尝试将事件加载到日历中 因此,我需要使用事件数据创建一个JSONstring,但我不知道如何实现 如何创建数据:Php 如何正确格式化JSON Laravel 5.5,php,json,laravel,laravel-5,Php,Json,Laravel,Laravel 5,我正在尝试将事件加载到日历中 因此,我需要使用事件数据创建一个JSONstring,但我不知道如何实现 如何创建数据: $tickets = Ticket::where('mechanic_id', $request->mechanic_id)->get(); $tickets_json[] = []; foreach($tickets as $ticket) { $tickets_json['title'] = $ticket->number; $tick
$tickets = Ticket::where('mechanic_id', $request->mechanic_id)->get();
$tickets_json[] = [];
foreach($tickets as $ticket) {
$tickets_json['title'] = $ticket->number;
$tickets_json['start'] = $ticket->planned_timestamp_start->format('d-m-Y H:i');
$tickets_json['end'] = $ticket->planned_timestamp_end->format('d-m-Y H:i');
$tickets_json['url'] = '/tickets/' . $ticket->id;
}
这将返回:
array:5 [▼
0 => []
"title" => "452"
"start" => "27-10-2017 09:00"
"end" => "27-10-2017 12:00"
"url" => "/tickets/2"
]
这不是我想要和需要的
我需要这样:
{
title: '63782136',
start: '27-10-2017 09:00',
end: '"27-10-2017 12:00"',
url: '/tickets/2'
},
{
title: '23123',
start: '27-10-2017 09:00',
end: '"27-10-2017 12:00"',
url: '/tickets/3'
},
{
title: '432512',
start: '27-10-2017 09:00',
end: '"27-10-2017 12:00"',
url: '/tickets/4'
},
我试过:
returnresponse()->json($tickets\u json)代码>
但不返回正确的格式:
#data: "{"0":[],"title":"452","start":"27-10-2017 09:00","end":"27-10-2017 12:00","url":"\/tickets\/2"}"
它添加了{“0”:[],}
提前感谢。当您希望将数据分配到数组的第一维度时,您犯了将数据分配到数组的第二维度的错误。下面应该可以做到这一点:
$tickets_json = [];
$tickets->each(function ($ticket) use (&$tickets_json) {
$tickets_json[] = [
'title' => $ticket->numer,
'start' => $ticket->planned_timestamp_start->format('d-m-Y H:i'),
'end' => $ticket->planned_timestamp_end->format('d-m-Y H:i'),
'url' => '/tickets/' . $ticket->id
];
});
return $tickets_json;
此代码将为您提供一个正确的格式化数组,您可以使用该数组获得以下JSON输出:
[
{
"title": "63782136",
"start": "27-10-2017 09:00",
"end": "27-10-2017 12:00",
"url": "/tickets/2"
},
{
"title": "23123",
"start": "27-10-2017 09:00",
"end": "27-10-2017 12:00",
"url": "/tickets/3"
}
]
当您希望将数据分配到数组的第一维度时,您犯了将数据分配到数组的第二维度的错误。下面应该可以做到这一点:
$tickets_json = [];
$tickets->each(function ($ticket) use (&$tickets_json) {
$tickets_json[] = [
'title' => $ticket->numer,
'start' => $ticket->planned_timestamp_start->format('d-m-Y H:i'),
'end' => $ticket->planned_timestamp_end->format('d-m-Y H:i'),
'url' => '/tickets/' . $ticket->id
];
});
return $tickets_json;
此代码将为您提供一个正确的格式化数组,您可以使用该数组获得以下JSON输出:
[
{
"title": "63782136",
"start": "27-10-2017 09:00",
"end": "27-10-2017 12:00",
"url": "/tickets/2"
},
{
"title": "23123",
"start": "27-10-2017 09:00",
"end": "27-10-2017 12:00",
"url": "/tickets/3"
}
]
更改$tickets\u json[]=[]代码>到$tickets\u json=[]代码>。但我需要一列多张票只需返回$tickets?如果您要发出get请求,默认情况下,它会将数据转换为json数组代码>到$tickets\u json=[]代码>。但我需要一列多张票只需返回$tickets?如果你发出get请求,默认情况下它会将数据转换成json数组。天哪,这正是我所需要的。非常感谢您在批准期限允许的情况下批准我的回答。天哪,这正是我所需要的。非常感谢您在批准限额允许的情况下批准回答。