在php中定义数组的数组

我在php中定义了一个数组，如下所示

<?php

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

echo $Type[0];


?>

当我试图打印时，它说Err:无法将数组转换为字符串 这种声明方式正确吗？？如果没有，您可以共享您的视图。

它不能回显$Type[0]，因为它是一个数组。可以使用print\r打印阵列

---

如果你想调试你的变量，看看它们是什么样子，一个简单的解决方案就是var_dump em

但是你没有做错任何事，除非你不能回显一个数组。举个例子，这是一个合法的打印语句

echo $Type[0][0];

---

试试看结果-

<?php

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

var_dump($Type);


?>

---

您认为$Type[0]包含哪些内容？请使用for循环来打印。。或者var_dump在处理arraysVar_dump时，您应该始终使用print_r，这样即使没有更好的结果，也会得到类似的结果，谢谢分享@泰利

echo $Type[0][0];

<?php

$Category = array("Apparel","Grocery","Health","Gift","Footwear","Jewelry","Food & Bev");
$Shops = array("Giny & Jony","Big Bazaar","Health & Glow","Factory Outlet Store","Archies","Bata","100 Rs Shop","Silver Touch","Sri Devi Traders","Avatar","Steamzz");
$Type = array($Category,$Shops); 

var_dump($Type);


?>