Plsql Oracle11g：使用字典映射替换部分字符串

使用字典映射更改字符串中的值有什么好方法吗？例如，我有

表1

和一些映射表

dict1

：

我需要一些

SELECT

语句，该语句将拆分

表1中的值。行1

并使用映射字典

dict1

更改单词，以便接收到的值（将现有字典值更改为上限是可选的）：

另外，使用REGEXP表达式拆分将非常好

WITH dict1 AS
 (SELECT 'THIS' fr,
         'THAT' t
    FROM dual
  UNION ALL
  SELECT 'IS' fr,
         'ARE' t
    FROM dual
  UNION ALL
  SELECT 'EXAMPLE' fr,
         'SOURCE' t
    FROM dual
  UNION ALL
  SELECT 'STRING' fr,
         'NUMBER' t
    FROM dual),
table1 AS
 (SELECT 'This is an example string' AS str,
         1 AS sn
    FROM dual
  UNION ALL
  SELECT 'This String has typ0s' AS str,
         2 sn
    FROM dual),
src AS
 (SELECT regexp_substr(upper(s.str), '[^ ]+', 1, LEVEL) str2,
         s.*,
         rownum nn
    FROM table1 s
  CONNECT BY instr(TRIM(' ' FROM str), ' ', 1, LEVEL - 1) > 0
         AND PRIOR sn = sn
         AND PRIOR dbms_random.value IS NOT NULL),
repl AS
 (SELECT nvl2(dict1.t, dict1.t, src.str2) lex,
         sn,
         nn
    FROM src
    LEFT JOIN dict1
      ON dict1.fr = src.str2)
SELECT listagg(lex, ' ') within GROUP(ORDER BY nn),
       sn
  FROM repl
 GROUP BY sn

它现在可以按你的要求工作了。享受

---

编辑：使用解决方案

您介意函数中的PLSQL吗？非常令人印象深刻。。但您能否解释一下为什么要添加

和先前的dbms_random.value不为NULL

？以便在解析字符串时消除可能的循环。有时候，当我们在一个字符串中有相等的值时，比如“oo bb oo”，根据你的回答，我修改了我的小提琴，因为我可以看到它返回你想要的东西，所以我很高兴：）

+-------------------------+
|     OLD    |    NEW     |
+-------------------------+
| THIS       | THAT       |
| IS         | ARE        |
| EXAMPLE    | SOURCE     |
| STRING     | NUMBER     |
+------------+------------+

+---------------------------+
|      TRANS_ROW1           |
+---------------------------+
| THAT ARE AN SOURCE NUMBER |
| THAT NUMBER HAS TYP0S     |
+---------------------------+

WITH dict1 AS
 (SELECT 'THIS' fr,
         'THAT' t
    FROM dual
  UNION ALL
  SELECT 'IS' fr,
         'ARE' t
    FROM dual
  UNION ALL
  SELECT 'EXAMPLE' fr,
         'SOURCE' t
    FROM dual
  UNION ALL
  SELECT 'STRING' fr,
         'NUMBER' t
    FROM dual),
table1 AS
 (SELECT 'This is an example string' AS str,
         1 AS sn
    FROM dual
  UNION ALL
  SELECT 'This String has typ0s' AS str,
         2 sn
    FROM dual),
src AS
 (SELECT regexp_substr(upper(s.str), '[^ ]+', 1, LEVEL) str2,
         s.*,
         rownum nn
    FROM table1 s
  CONNECT BY instr(TRIM(' ' FROM str), ' ', 1, LEVEL - 1) > 0
         AND PRIOR sn = sn
         AND PRIOR dbms_random.value IS NOT NULL),
repl AS
 (SELECT nvl2(dict1.t, dict1.t, src.str2) lex,
         sn,
         nn
    FROM src
    LEFT JOIN dict1
      ON dict1.fr = src.str2)
SELECT listagg(lex, ' ') within GROUP(ORDER BY nn),
       sn
  FROM repl
 GROUP BY sn