Postgresql 我怎样才能过滤所有打开的店主？

这是我的桌子。我想根据“日期\登记簿”字段的最后一个登记簿了解店主是开还是关。例如，shopkeeper=79最后一个状态为Close，则不会在查询中返回该状态

比如：

SELECT 
    distinct on(shopkeeper_id) shopkeeper_id, state, date_register
FROM  
   shopkeepers_state
WHERE 
    state = 'Open'
ORDER BY 
    shopkeeper_id, date_register DESC;

从

SELECT *, rank() OVER (PARTITION BY shopkeeper_id ORDER BY date_register DESC)
FROM shopkeepers_state 

这将为您提供一个具有排名计数的表，以便每个店主id的排名1指向最近的条目。 以此为基础，应用过滤器：

SELECT * FROM
(SELECT *, rank() OVER (PARTITION BY shopkeeper_id ORDER BY date_register DESC)
    FROM shopkeepers_state) AS ps
WHERE ps.rank = 1
AND ps.state = 'Open'

---

我想得到->然后去做！从这里开始：