Postgresql plgpsql-是否可以声明一组记录或表变量？

我有以下-不工作-功能：

CREATE FUNCTION permission_cache_update(affected_user_list int[])
  RETURNS TABLE(user_id INT4, permission_id INT4)
AS
  $BODY$
  DECLARE
    current_relations SETOF RECORD;
  BEGIN

  WITH
  affected_user AS (
     SELECT unnest(affected_user_list) AS u_id
  ),
  affected_relations AS (
    SELECT user_role.user_id, role_permission.permission_id
      FROM   user_role
      JOIN   role_permission ON user_role.role_id = role_permission.role_id
      JOIN   affected_user ON affected_user.u_id = user_role.user_id
    UNION
    SELECT user_permission.user_id, user_permission.permission_id
      FROM   user_permission
      JOIN   affected_user ON affected_user.u_id = user_permission.user_id
  )
  SELECT affected_relations.user_id, affected_relations.permission_id FROM affected_relations
  INTO current_relations;

  DELETE FROM permission_cache WHERE ARRAY[user_id] <@ affected_user_list;
  INSERT INTO permission_cache (user_id, permission_id) SELECT user_id, permission_id FROM current_relations;

  END
  $BODY$
LANGUAGE plpgsql;

我认为这是可能的表->二维数组转换，但这是复杂的，所以如果它可能与记录，这将是更好的

解决方案：

使用1d数组创建循环比使用记录或2d数组更容易：

CREATE FUNCTION permission_cache_update(
  IN affected_user_list INT4 []
)
  RETURNS VOID
AS
  $BODY$
  DECLARE
    user_index                    INT4;
    current_user_id INT4;
    current_permission_relations  INT4 [];
    deleted_permission_relations  INT4 [];
    inserted_permission_relations INT4 [];
  BEGIN
    FOR user_index IN 1 .. array_upper(affected_user_list, 1) LOOP
      current_user_id := affected_user_list[user_index];

      WITH
          user_permission_summary AS
        (
          SELECT
            role_permission.permission_id
          FROM user_role, role_permission
          WHERE role_permission.role_id = user_role.role_id AND user_role.user_id = current_user_id
          UNION
          SELECT
            user_permission.permission_id
          FROM user_permission
          WHERE user_permission.user_id = current_user_id
        )
      SELECT
        array_agg(permission_id)
      FROM user_permission_summary
      INTO current_permission_relations;

    SELECT
      array_agg(permission_cache.permission_id)
    FROM permission_cache
    WHERE permission_cache.user_id = current_user_id AND ( current_permission_relations IS NULL OR
          NOT (ARRAY [permission_cache.permission_id] <@ current_permission_relations) )
    INTO deleted_permission_relations;

    SELECT
      array_agg(inserted_permission_id)
    FROM unnest(current_permission_relations) AS inserted_permission_id
    WHERE NOT EXISTS(SELECT
                       1
                     FROM permission_cache
                     WHERE permission_cache.user_id = current_user_id AND
                           permission_cache.permission_id = inserted_permission_id)
    INTO inserted_permission_relations;

    DELETE FROM permission_cache
    WHERE permission_cache.user_id = current_user_id AND
          permission_cache.permission_id = ANY (deleted_permission_relations);

    INSERT INTO permission_cache (user_id, permission_id)
      SELECT
        current_user_id,
        inserted_permission_id
      FROM unnest(inserted_permission_relations) AS inserted_permission_id;

    END LOOP;
  END;
  $BODY$
LANGUAGE plpgsql VOLATILE;

关： Pplpgsql是一种非常糟糕的语言，文档甚至很糟糕，我不喜欢它。。。 很抱歉，代码格式化，我的IDE中的自动格式化不太好…：S

我认为这个简化的SQL函数可以满足您的需要：

CREATE FUNCTION permission_cache_update(affected_user_list int[])
  RETURNS void AS
$func$

DELETE FROM permission_cache p
USING (SELECT unnest($1) AS u_id) a
WHERE  p.user_id = a.u_id;

INSERT INTO permission_cache (user_id, permission_id)
SELECT u.user_id, r.permission_id
FROM   user_role u
JOIN   role_permission r USING (role_id)
JOIN  (SELECT unnest($1) AS u_id) a ON a.u_id = u.user_id
UNION
SELECT p.user_id, p.permission_id
FROM   user_permission p
JOIN  (SELECT unnest($1) AS u_id) a ON a.u_id = p.user_id;

$func$ LANGUAGE sql;

将极大地简化这一过程，但仅在Postgres 9.1中引入。再一次，你过时的版本挡道了

---

仅在Postgres 9.2中为plpgsql的早期SQL函数引入了按名称引用参数。所以我使用位置参数$1。

您仍然声明：返回TABLEuser\u id INT4，permission\u id INT4。这是一个工件还是你真的想额外返回行？哦，不：D这只是以前代码的一部分…是的，但我不想简化，在这个函数的下一个版本中，我将删除并插入真正需要的内容。。。我想了想，二维数组可以吗？我认为有记录和没有循环是不可能的。。。记录集不工作，我不认为有记录数组这样的东西……@inf3rno：当然有这样的东西。您可以使用多维数组或记录数组，即使在良好的旧Postgres 8.4中也是如此。我回答了一个问题。8.4的工作原理与此相同。顺便说一句，临时桌子怎么了？对于更大的场景，这通常更快。在现代的博士后考试中，你可能只需要一个数据修改CTE就可以完成这一切。

CREATE FUNCTION permission_cache_update(affected_user_list int[])
  RETURNS void AS
$func$

DELETE FROM permission_cache p
USING (SELECT unnest($1) AS u_id) a
WHERE  p.user_id = a.u_id;

INSERT INTO permission_cache (user_id, permission_id)
SELECT u.user_id, r.permission_id
FROM   user_role u
JOIN   role_permission r USING (role_id)
JOIN  (SELECT unnest($1) AS u_id) a ON a.u_id = u.user_id
UNION
SELECT p.user_id, p.permission_id
FROM   user_permission p
JOIN  (SELECT unnest($1) AS u_id) a ON a.u_id = p.user_id;

$func$ LANGUAGE sql;