PostgreSQL自定义周数-包含2月1日的第一周
我不熟悉SQL函数,并尝试创建一个日历表,其中显示自定义周数,每周从周六开始,周五结束。每年的第一周总是包含当年的2月1日。 例如,如果某一年的2月1日是星期二,那么该年的第一周是从1月29日到2月4日 我已经为这个问题挣扎了几天,我能想出的唯一解决办法如下: 首先,我创建了一个日历表,其中包含一个名为“CustomizedWeekNo”的列,以反映从包含2月1日的一周开始的一年周期。但每周的第一天是星期一PostgreSQL自定义周数-包含2月1日的第一周,postgresql,customization,plpgsql,sql-function,week-number,Postgresql,Customization,Plpgsql,Sql Function,Week Number,我不熟悉SQL函数,并尝试创建一个日历表,其中显示自定义周数,每周从周六开始,周五结束。每年的第一周总是包含当年的2月1日。 例如,如果某一年的2月1日是星期二,那么该年的第一周是从1月29日到2月4日 我已经为这个问题挣扎了几天,我能想出的唯一解决办法如下: 首先,我创建了一个日历表,其中包含一个名为“CustomizedWeekNo”的列,以反映从包含2月1日的一周开始的一年周期。但每周的第一天是星期一 Create Table Calendar (CalendarDate Date, We
Create Table Calendar
(CalendarDate Date, WeekNo smallInt, WeekDayNo text, CustomizedWeekNo smallInt)
Create or Replace Function CustomizeWeekNumber()
Returns void
as $$
Declare beginDate Date :='2015-01-31'; endDate Date := '2017-01-27';
Begin
While beginDate <= endDate loop
Insert Into Calendar (CalendarDate, WeekNo, WeekDayNo, CustomizedWeekNo)
Select
beginDate As CalendarDate
,DATE_PART('week', beginDate::timestamp)::smallint As WeekNo
,(Case When DATE_PART('isodow', beginDate::timestamp)::smallint = 6
Then 'Sat'
When DATE_PART('isodow', beginDate::timestamp)::smallint = 7
Then 'Sun'
When DATE_PART('isodow', beginDate::timestamp)::smallint = 1
Then 'Mon'
When DATE_PART('isodow', beginDate::timestamp)::smallint = 2
Then 'Tue'
When DATE_PART('isodow', beginDate::timestamp)::smallint = 3
Then 'Wed'
When DATE_PART('isodow', beginDate::timestamp)::smallint = 4
Then 'Thur'
Else 'Fri'
End) As WeekDayNo;
,(Case When beginDate < '2016-01-04'
Then DATE_PART('week', beginDate::timestamp)::smallint - 5
When beginDate >= '2016-01-04' and beginDate < '2016-01-30'
Then (date_part('week', '2016-01-03'::timestamp)::smallint - 5 + date_part('week', beginDate::timestamp)::smallint)
When beginDate >= '2016-01-30' and beginDate < '2017-01-02'
Then date_part('week', beginDate::timestamp)::smallint - 4
Else
date_part('week', '2017-01-01'::timestamp)::smallint - 4 + date_part('week', beginDate::timestamp)::smallint
End) As CustomizedWeekNo;
Select (beginDate + interval'1 day') into beginDate;
End loop;
End; $$
language plpgsql;
# Run the function
select CustomizeWeekNumber()
最后,我创建了另一个函数来返回我需要的信息。我还重新格式化了“CustomizedWeekNo”的值,以包含特定年份
create or replace function update_CustomizedWeek(date, date)
returns table(Calendar_Date Date, Week_No int, WeekDay_No text, Customized_Week_No int)
as $$
begin
return query
select t.CalendarDate, t.WeekNo, t.WeekDayNo,
case when t.CustomizedWeekNo <= 9
then (date_part('year', t.CalendarDate::timestamp)::text||'0'||t.CustomizedWeekNo::text)::int
else (date_part('year', t.CalendarDate::timestamp)::text||t.CustomizedWeekNo::text)::int
end
from Calendar t
where t.CalendarDate >= $1 and t.CalendarDate <= $2
order by t.CalendarDate;
end; $$
language plpgsql;
--Example
select * from update_CustomizedWeek('2015-01-30', '2015-02-10')
正如你所看到的,我在这里使用了很多“硬编码”。我希望能够为任何年份生成一个日期范围以及定制的周数,而不仅仅是2016年或2017年。非常感谢您的帮助 截断到上一个星期一。您仍然可以通过在输入中添加2天(Sat和Mon之间的差异)来使用它,然后从输出中减去2天。工作完美
此查询准确地生成所需的输出:
只需提供相应年份的2月3日:时间戳“2015-02-03”
create or replace function update_CustomizedWeek(date, date)
returns table(Calendar_Date Date, Week_No int, WeekDay_No text, Customized_Week_No int)
as $$
begin
return query
select t.CalendarDate, t.WeekNo, t.WeekDayNo,
case when t.CustomizedWeekNo <= 9
then (date_part('year', t.CalendarDate::timestamp)::text||'0'||t.CustomizedWeekNo::text)::int
else (date_part('year', t.CalendarDate::timestamp)::text||t.CustomizedWeekNo::text)::int
end
from Calendar t
where t.CalendarDate >= $1 and t.CalendarDate <= $2
order by t.CalendarDate;
end; $$
language plpgsql;
--Example
select * from update_CustomizedWeek('2015-01-30', '2015-02-10')
Calendar_Date | Week_No | WeekDay_No | Customized_Week_No
------------- | ------- | ---------- | -------------------
2015-01-31 | 5 | Sat | 201501
2015-02-01 | 5 | Sun | 201501
2015-02-02 | 6 | Mon | 201501
2015-02-03 | 6 | Tue | 201501
2015-02-04 | 6 | Wed | 201501
2015-02-05 | 6 | Thur | 201501
2015-02-06 | 6 | Fri | 201501
2015-02-07 | 6 | Sat | 201502
2015-02-08 | 6 | Sun | 201502
2015-02-09 | 7 | Mon | 201502
2015-02-10 | 7 | Tue | 201502
SELECT d::date AS "Calendar_Date"
, EXTRACT('WEEK' FROM d)::int AS "Week_No"
, to_char(d, 'Dy') AS "WeekDay_No"
, base_nr + (rn::int - 1) / 7 AS "Customized_Week_No"
FROM (
SELECT date_trunc('week', feb3) - interval '2 days' AS day1 -- subtract 2 days
, EXTRACT('year' FROM feb3)::int * 100 + 1 AS base_nr
FROM (SELECT timestamp '2015-02-03') input(feb3) -- add 2 days, so Feb 3 (!)
) t, generate_series (day1
, day1 + interval '1 year - 1 day'
, interval '1 day') WITH ORDINALITY AS d(d, rn);