Python 2.7 修复while循环

如何修复此代码中的while循环，使其仅在

age

为18时工作，如果小于18，则打印错误消息，并使程序在输入错误的邮政编码后继续运行

这是我的密码：

print "VOTER ELIGIBILITY AND POLLING STATION PROGRAM"
print
print
age= int(raw_input("Enter your age (Type ' 0 ' to exit program) :"))
while age != 18:
    print "ineligible"
    age= int(raw_input("Enter your age (Type ' 0 ' to exit program) :"))
    if age != 0:
        zipcode= int(raw_input("Enter your residence's zip code:"))

        if zipcode == 93305:
            print "Your polling station is 123 Panorama Drive."
        elif zipcode == 93306:
            print "Your polling station is 6143 Fairfax Drive."
        elif zipcode ==93307:
            print "Your polling station is 21121 B Street."
        elif zipcode ==93308:
            print "Your polling station is 863 Desmond Ct."
        elif zipcode == 93309:
            print "Your polling station is 7332 Del Canto Ct."
        else:
            print "Error-unknown zip code"

raw_input("\nRun complete.Press the Enter key to exit.")    

尝试以下方法：

age = get_age();

while ( age != 0 ) {
    if ( age >= 18 ) ...
    else ...

    age = get_age();
}

exit

---

如果你想看到示例运行，我会运行它，但即使我输入了18岁以下的年龄，它仍然会执行zipcode块。现在你可能有缩进问题。尝试将相关部分重新键入一个单独的文件。我将它复制到一个文本编辑器中（在我的答案中进行了修改），使缩进统一，并且运行良好。这里有一个指向代码的链接，这正是我的代码，它适合我。也许你的压痕掉了。