Python 2.7 Tic tac toe程序（Python）中出错

下面显示的代码是一个Tic-tac-toe游戏的代码，其中有两个玩家（Player1和Player2是人类）。代码中“#Player 1立即播放”和“#Player 2立即播放”部分的if-else语句中有一个问题。确切地说，计算机总是认为每个框中都已填充了除1、2、3、4、5、6、7、8、9以外的其他值，并不断显示嵌套else语句中定义的消息“该单元格已标记。请尝试另一个单元格”。 有人能告诉我如何解决这个问题吗

board = [0,1,2,3,4,5,6,7,8,9]
print type(board[1])
def board_invoke():
print "| ",board[1], " | ", board[2], " | ", board[3], " | ", "\n", "-------------------", "\n", "| ", board[4], " | ",board[5], " | ", board[6], " | ", "\n", "-------------------", "\n", "| ",  board[7], " | ",board[8], " | ", board[9], " | "

def game_start():
Player1= raw_input("Select Player 1 between X or O : ")
if Player1 not in ('X','x','O','o'):
    print "That is not an expected player"
    game_start()
else:
    print "\nSince you have selected Player 1 as %s" %Player1
    print "\nThe Player 2 is assigned :",
    if Player1 in ('X','x'):
        Player2 = ("O")
    else:
        Player2 = ("X")
    print Player2
    print "\nThe game Starts now....\n"
    board_invoke()
    while (1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9) in board:

        # Winning Condition
        if board[1]==board[2]==board[3]==Player1:
            print Player1," wins"
            break
        elif board[4]==board[5]==board[6]==Player1:
            print Player1, " wins"
            break
        elif board[7]==board[8]==board[9]==Player1:
            print Player1, " wins"
            break
        elif board[1]==board[2]==board[3]==Player2:
            print Player2, " wins"
            break
        elif board[4]==board[5]==board[6]==Player2:
            print Player2, " wins"
            break
        elif board[7]==board[8]==board[9]==Player2:
            print Player2, " wins"
            break
        elif board[1]==board[5]==board[9]==Player1:
            print Player1, " wins"
            break
        elif board[3]==board[5]==board[7]==Player1:
            print Player1, " wins"
            break
        elif board[1]==board[5]==board[9]==Player2:
            print Player2, " wins"
            break
        elif board[3]==board[5]==board[7]==Player2:
            print Player2, " wins"
            break
        elif board[1]==board[4]==board[7]==Player1:
            print Player1, " wins"
            break
        elif board[2]==board[5]==board[8]==Player1:
            print Player1, " wins"
            break
        elif board[3]==board[6]==board[9]==Player1:
            print Player1, " wins"
            break
        elif board[1]==board[4]==board[7]==Player2:
            print Player2, " wins"
            break
        elif board[2]==board[5]==board[8]==Player2:
            print Player2, " wins"
            break
        elif board[3]==board[6]==board[9]==Player2:
            print Player2, " wins"
            break

        # Player 1 Plays now

        Cell_no = raw_input("Player 1 : Please select a number you want to mark....")
        Cell_no = int(Cell_no)

        if Cell_no not in board:
            print "Please enter a cell number within the scope of available cells"
        else:
            if 'X' or 'x' or 'O' or 'o' in board[Cell_no]:
                print "That cell is already marked. Please try another cell"
                continue
            else:
                board[Cell_no] = Player1
                board_invoke()

        # Player 2 Plays now

        Cell_no = raw_input("Player 2 : Please select a number you want to mark....")
        Cell_no = int(Cell_no)

        if Cell_no not in board:
            print "Please enter a cell number within the scope of available cells"
        else:
            if 'X' or 'x' or 'O' or 'o' in board[Cell_no]:
                print "That cell is already marked. Please try another cell"
                continue
            else:
                board[Cell_no] = Player2
                board_invoke()

    print "Do you want to play again ?"
    user_decision = raw_input("Please type Yes or No : ")
    if user_decision == ('YES' or 'Yes' or 'yes'):
        game_start()
    else:
        print "Ok. I take it that we will wrap up !"
        print "See you again !"



game_start()

---

你的if语句不完全正确。 您正在评估：

这总是正确的。

或

关键字以逻辑方式组合每个比较。第一个compare语句就是

'X'

，它不是null或0，因此总是true。因为第一条语句为真，所以整个if语句为真

我经常在开始学习编程的人身上看到这种情况。如果语句不能完全像人类句子那样书写。必须将每个字符与变量进行比较。 下面是一个简单（不是特定于python的，而且相当难看）的解决方案：

else:
 if 'X' == board[Cell_no] or 'x' == board[Cell_no] or 'O' == board[Cell_no] or 'o' == board[Cell_no]:
      print "That cell is already marked. Please try another cell"

但更好的方法是将该检查转过来，并将其与列表进行比较：

else:
 if board[Cell_no] in ['X','x', 'O', 'o']:
      print "That cell is already marked. Please try another cell"

else:
 if board[Cell_no] in ['X','x', 'O', 'o']:
      print "That cell is already marked. Please try another cell"