Python 2.7 您可以为Tkinter选项菜单分配多个命令吗?
我有以下选项菜单:Python 2.7 您可以为Tkinter选项菜单分配多个命令吗?,python-2.7,tkinter,Python 2.7,Tkinter,我有以下选项菜单: self.wcartsn = StringVar(self.frame1) self.e1 = OptionMenu(self.frame1, self.wcartsn, *watercarts, command=(self.wcart, lambda selection:self.other_entry(selection,'wcartsn',10,6)))
self.wcartsn = StringVar(self.frame1)
self.e1 = OptionMenu(self.frame1, self.wcartsn, *watercarts, command=(self.wcart, lambda selection:self.other_entry(selection,'wcartsn',10,6)))
self.e1.grid(row=10, column=5, stick=E+W)
这实际上不起作用,但它清楚地说明了我的问题如何(如果可能)从一个选项菜单调用多个函数?此函数给出错误
TypeError:“tuple”对象不可调用
您可以创建一个函数,依次调用多个函数:
def compose(functions):
"""
returns a single function composed from multiple functions.
calling the returned function will execute each of the functions in the order you gave them.
"""
def f(*args, **kargs):
for function in functions:
function(*args, **kargs)
return f
self.e1 = OptionMenu(self.frame1, self.wcartsn, *watercarts, command=compose(self.wcart, lambda selection:self.other_entry(selection,'wcartsn',10,6)))
最简单的解决方案——也是最容易维护的解决方案——是创建一个调用其他函数的函数:
def __init__(self):
...
self.wcartsn = StringVar(self.frame1)
self.e1 = OptionMenu(self.frame1, self.wcartsn, *watercarts, command=self.wcartsnCallback)
...
def wcartsnCallback(self, selection):
self.wcart()
self.other_entry(selection,'wcartsn',10,6)