Python 3.x 如何将此函数压缩为从列表返回值?
我知道这可能不是最佳做法或常规做法,但这更多的是个人挑战Python 3.x 如何将此函数压缩为从列表返回值?,python-3.x,list-comprehension,Python 3.x,List Comprehension,我知道这可能不是最佳做法或常规做法,但这更多的是个人挑战 def initialize_dataset(source): all_features = [] targets = [] for (sent, label) in source: feature_list=[] feature_list.append(avg_number_chars(sent)) feature_list.append(number_words(
def initialize_dataset(source):
all_features = []
targets = []
for (sent, label) in source:
feature_list=[]
feature_list.append(avg_number_chars(sent))
feature_list.append(number_words(sent))
all_features.append(feature_list)
targets.append(0) if label=="austen" else targets.append(1)
return all_features, targets
我正在寻找的例子。我理解可能无法将其归结为一个列表和/或值。但有点接近。我想扩展一下我对写作清单理解的思考
def sample_function(data):
return [i for i in data ]
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