Python 3.x 如何在循环的第一个实例中跳过前三个元素

如何使用python实现这一点

for season in seasons:
    print('Season:',season)
    season_response = requests.get(season, headers=headers, cookies=cookies)
    season_content = season_response.content
    season_doc = html.fromstring(season_content)
    dates = [base + date for date in season_doc.xpath('//*[@id="bloccontenu"]//div[@class="select-container select-game"]/select/option/@value')]
    for date in dates:
        print(date)
        # print dates
        # exclude the first three dates of only the first instance of loop

如何打印不包括第一季的前三个日期，但每隔一季打印所有其他日期

例如，第1季有6个日期，第2季有5个日期： 我期望这样的输出，其中第1季的前3个日期被排除在外：

Season: season 1  
date4
date5
date6
Season: season 2
date1
date2
date3
date4
date5

---

当季节等于季节1时，放弃前3个日期？

你能在

季节中发布前两个元素的（简化版，如有必要）版本吗？

？谢谢@Juke。你的回答实际上让我知道该怎么办。如果季节==季节[0]：日期=日期[3:]

for season in seasons:
    print('Season:',season)
    season_response = requests.get(season, headers=headers, cookies=cookies)
    season_content = season_response.content
    season_doc = html.fromstring(season_content)
    dates = [base + date for date in season_doc.xpath('//*[@id="bloccontenu"]//div[@class="select-container select-game"]/select/option/@value')]

    if season == seasons[0]:
        dates = dates[3:]

    for date in dates:
        print(date)