Python 3.x Python示意图忽略rogue字段名,但验证其值
假设我有以下JSON:Python 3.x Python示意图忽略rogue字段名,但验证其值,python-3.x,orm,python-schematics,Python 3.x,Orm,Python Schematics,假设我有以下JSON: { "name": "Rob", "Occupation": { "Painter": [ { "company" : "X", "years" : "1980-1997" }, { "company" : "Y", "yea
{
"name": "Rob",
"Occupation": {
"Painter": [
{
"company" : "X",
"years" : "1980-1997"
},
{
"company" : "Y",
"years" : "1999-2000"
}
],
"Singer": [
{
"company" : "A",
"years" : "2001-2005"
}
]
}
}
“画家”和“歌手”的“职业”领域显然可以转变为其他领域。如何使用schematics
到目前为止,我有以下资料:
from schematics import models, types
class Person(models.Model):
name = types.StringType()
occupation = types.ModelType(OccupationModel, serialized_name="Occupation")
class Occupation(models.Model):
## Here is where I don't know what to do!!!
因此,经过大量的修补,终于找到了一种方法来做到这一点。有趣的是,在schematics模块的test case文件夹中找到了一个示例: 下面是我最后做的:
class OccupationModel(models.Model):
company = types.StringType()
years = types.StringType()
class Person(models.Model):
name = types.StringType()
occupation = types.DictType(types.ListType(types.ModelType(OccupationModel)), serialized_name="Occupation")