Python 3.x 客户端如何获得服务器上传的文件名和扩展名的原始文件？

请帮助我，我只是python的初学者，我想学习这个。我不知道如何从服务器部件获取原始文件名和扩展名

我尝试了很多方法和研究，但仍然不能工作。我看到了许多类型的示例，它们只能上载带有

的文本文件，在客户端部分中以open（'received_file'，'.txt'，'wb'）作为f:

，并且不能上载文件的多类型扩展名。我知道，因为有

'.txt'

，所以只需处理文本文件即可。我不知道如何声明获得多个扩展名和原始文件名。这是我的原始代码

client


import socket
import os
TCP_IP = 'localhost'
TCP_PORT = 9001
BUFFER_SIZE = 8192

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((TCP_IP, TCP_PORT))
#data = s.recv(BUFFER_SIZE)


with open('received_file','.txt','wb') as f:
    print ('file opened')
    while True:
        print('receiving data...')
        data = s.recv(BUFFER_SIZE)
        print('data=%s', (data))
        if not data:
            f.close()
            print ('file close()')
            break
        # write data to a file
        f.write(data)

print('Successfully get the file')
s.close()
print('connection closed')

大宗报价

---

接收到的输出文件名为\u file，不带扩展名

您需要定义一个传输文件名和数据的协议。下面的示例将

input.txt

的内容作为文件名

output.txt

传输到客户端。客户端读取文件名，然后将数据写入该文件名。我之所以这样做，只是因为客户端和服务器运行在同一台计算机上，并且在同一个目录中读取/写入文件

server.py

import socketserver

class MyTCPHandler(socketserver.BaseRequestHandler):
    def handle(self):
        filename = 'output.txt'
        self.request.sendall(filename.encode() + b'\r\n')
        with open('input.txt','rb') as f:
            self.request.sendall(f.read())

if __name__ == "__main__":
    HOST, PORT = "localhost", 9001
    with socketserver.ThreadingTCPServer((HOST, PORT), MyTCPHandler) as server:
        server.serve_forever()

import socket
import os
SERVER = 'localhost',9001

s = socket.socket()
s.connect(SERVER)

# autoclose f and s when with block is exited.
# makefile treats the socket as a file stream.
# Open in binary mode so the bytes of the file are received as is.
with s,s.makefile('rb') as f:
    # The first line is the UTF-8-encoded filename.  Strip the line delimiters.
    filename = f.readline().rstrip(b'\r\n').decode()
    with open(filename,'wb') as out:
        out.write(f.read())

client.py

import socketserver

class MyTCPHandler(socketserver.BaseRequestHandler):
    def handle(self):
        filename = 'output.txt'
        self.request.sendall(filename.encode() + b'\r\n')
        with open('input.txt','rb') as f:
            self.request.sendall(f.read())

if __name__ == "__main__":
    HOST, PORT = "localhost", 9001
    with socketserver.ThreadingTCPServer((HOST, PORT), MyTCPHandler) as server:
        server.serve_forever()

import socket
import os
SERVER = 'localhost',9001

s = socket.socket()
s.connect(SERVER)

# autoclose f and s when with block is exited.
# makefile treats the socket as a file stream.
# Open in binary mode so the bytes of the file are received as is.
with s,s.makefile('rb') as f:
    # The first line is the UTF-8-encoded filename.  Strip the line delimiters.
    filename = f.readline().rstrip(b'\r\n').decode()
    with open(filename,'wb') as out:
        out.write(f.read())

---

抱歉，为什么我选择的文件将变为空，无法下载以创建新文件？@babolone如果客户端和服务器在同一系统上运行，则输入文件和输出文件不能使用相同的名称；否则，将在打开输出文件时覆盖输入文件。