Python 使用列表访问ndarray
你能通过索引列表访问Ndaray吗? 我使用了下面的脚本,但我认为它太重了Python 使用列表访问ndarray,python,numpy,Python,Numpy,你能通过索引列表访问Ndaray吗? 我使用了下面的脚本,但我认为它太重了 import numpy as np def getIndex(indice, data_num): index = 0 for i in range(len(data_num)): index += indice[i] * data_num[i] return index def at(ndarr, indice): indice_num = ndarr.shape
import numpy as np
def getIndex(indice, data_num):
index = 0
for i in range(len(data_num)):
index += indice[i] * data_num[i]
return index
def at(ndarr, indice):
indice_num = ndarr.shape
data_num = np.ones(ndarr.ndim)
for vi in range(len(indice_num)-1):
for ni in range(len(data_num)-vi-1):
data_num[ni] *= indice_num[len(indice_num)-vi-1]
print indice_num
print data_num
return ndarr.reshape(ndarr.size)[getIndex(indice, data_num)];
ndarr = np.array([[1., 2., 3.], [4., 5., 6.], [7., 8., 9.]])
print at(ndarr, [1,1,1]) # 5
是的,您只需要使用元组而不是列表:
>>> ndarr = np.array([[1., 2., 3.], [4., 5., 6.], [7., 8., 9.]])
>>> indices = [1,1] # row,col
>>> ndarr[tuple(indices)]
5.0
是的,您只需要使用元组而不是列表:
>>> ndarr = np.array([[1., 2., 3.], [4., 5., 6.], [7., 8., 9.]])
>>> indices = [1,1] # row,col
>>> ndarr[tuple(indices)]
5.0
??? 只是
ndarr[1,1]
???只是ndarr[1,1]